“去北京路采购备件” 英文怎么翻译?

1 Lucy often help my mother do the housework.
2 this is an important part of the lecture of Professor Li
3 Beijing road is we often go shopping.
4 this is a quiet place,there are many trees and flowers
5 Guangzhou is one of the biggest city in China

解题思路：本题可分别用未知数表示出两人的路程，再根据勾股定理列出方程求出未知数的值．

设经过x秒时两人相距85m，
根据题意得（4x）²+（50+3x）²=85²，
去括号得25x²+300x=4725，
即25x²+300x-4725=0，
化简得x²+12x-189=0，
∴（x-9）（x+21）=0，
解得x₁=9，x₂=-21（不符合实际情况，舍去），
当x=9时，4x=36，50+3x=77．
∴当两人相距85m时，甲在O点以东36m处，乙在O点以北77m处．
故当两人相距85米时，甲在O点以东36米处，乙在O点以北77米处．

点评：
本题考点： 一元二次方程的应用；勾股定理．

考点点评： 本题综合考查了方向角，一元二次方程的应用和勾股定理等知识点．要注意的是方向角问题中，南北和西东是垂直的．

Beijing Road,Kunming Panlong extension Jiangdong Good World Garden,No.3008,Block D

last Sunday.I was go shopping with my good friend in Beijing load.Today ,there had millons
of people in it.Everyone was busy.I went to a shoe shop to buy a shoe .In there ,the shoe was very beautiful.At last,I was bought a sport shoe .It's 36 size.I like it very much.
哈..好久没逛北京路了..

到了:get to/reach/arrive at/in
I reach the BeiJing road;
be careful to do sth:干什么请小心
Please be careful when you open the door,

解题思路：本题可分别用未知数表示出两人的路程，再根据勾股定理列出方程求出未知数的值．

设经过x秒时两人相距85m，
根据题意得（4x）²+（50+3x）²=85²，
去括号得25x²+300x=4725，
即25x²+300x-4725=0，
化简得x²+12x-189=0，
∴（x-9）（x+21）=0，
解得x₁=9，x₂=-21（不符合实际情况，舍去），
当x=9时，4x=36，50+3x=77．
∴当两人相距85m时，甲在O点以东36m处，乙在O点以北77m处．
故当两人相距85米时，甲在O点以东36米处，乙在O点以北77米处．

点评：
本题考点： 一元二次方程的应用；勾股定理．

考点点评： 本题综合考查了方向角，一元二次方程的应用和勾股定理等知识点．要注意的是方向角问题中，南北和西东是垂直的．

(1)设y=k/x,xy=10000,k=10000
（2）代入方程M点：当x1=10时,y1=1000;N点：当y2=10时,x2=1000
(3) 周长为500米时,半周长为250,即x+y=250,又∵y=10000/x,解方程组得∴x1=200,y1=50;x2=50,y2=200

多订购了：
40×（15×10%÷0.5），
=40×3，
=120（件）；

每个吉祥物实际出售价格为：
15×（1-10%），
=15×0.9，
=13.5（元）；

出售总额为：
13.5×（160+120），
=13.5×280，
=3780（元）；

这种商品的成本是：
（3780-160×15-180）÷120，
=1200÷120，
=10（元）；
答：这种商品的成本是10元．

Bei jing Road is the longest road of Kunming

1 He happened to meet with an awesome thing.
2 Her wallet was stolen by a thief when she was wondering on the Beijing Road.

如图,奥运圣火抵达某市奥林匹克广场后,沿图中直角坐标系中的一段反比例函数图象传递．动点 表示火炬位置,火炬从离北京路10米处的 点开始传递,到离北京路1000米的 点时传递活动结束．迎圣火临时指挥部设在坐标原点 （北京路与奥运路的十字路口）,为少先队员鲜花方阵,方阵始终保持矩形形状且面积恒为10000平方米（路线宽度均不计）．
（1）求图中反比例函数的关系式（不需写出自变量的取值范围）；
（2）求点M和点N的坐标.
（3）当鲜花方阵的周长为500米时,确定此时火炬的位置（用坐标表示）；
1)设y=k/x,xy=10000,k=10000
（2）代入方程M点：当x1=10时,y1=1000;N点：当y2=10时,x2=1000
(3) 周长为500米时,半周长为250,即x+y=250,又∵y=10000/x,解方程组得∴x1=200,y1=50;x2=50,y2=200
1)设y=k/x,xy=10000,k=10000
（2）代入方程M点：当x1=10时,y1=1000;N点：当y2=10时,x2=1000
(3) 周长为500米时,半周长为250,即x+y=250,又∵y=10000/x,解方程组得∴x1=200,y1=50;x2=50,y2=200

Tom, Jack's friend , fell ill in hospital . Jack was worried and wanted to see him after school . His mother told him how to get to the hospital .He needed to take the bus No 10 and got off at the Beijing Road Stop . Then he went along and turned at the third turning on the left , The hospital was right about 50 metres ahead .

There are a large number of shopping malls here with enough worldwide brands.If you wanner buy a cheap clothes with a fashnable style in Guangzhou,Beijing road is a good choice for you!

A Guide Book of Guangzhou City
Want to have a great time in Guangzhou? The Guide Book will help you a lot.
Sightseeing:
Baiyun Mountain. From the top you will see the whole city.
Shamian. You will enjoy many aged europen style buildings there.
Haixinsha Square. Best place to watch the modern buildings, such as Guangzhou Tower, Grand theater of Guangzhou and Guangdong Museum, and so on.
Delicious Food.
Baohua Road. It's the right place to taste every kind of delicious food.
Shopping.
Beijing Street. You can buy whatever you want in the malls.
What are you waiting for? Just start to serach the amazing tour in Guangzhou now!

新疆伊宁市北京路 金茂世界城小区 B2号楼 二单元202室
Room202, Unit 2, Building B2, JinmaoShijie Cheng, Beijing Road, Yi'ning, Xin'jiang

设时间x后两人相距85m时
（4x)^2+(3x)^2=(85)^2
25x^2=(85)^2
5x=85
x=17
4x=68
3x=51
甲在原点以东68m,乙在原点以北51m

A bad thing happened to him yesterday.
When she was walking around Beijing Road,a thief stole her purse and fled.

解题思路：本题可分别用未知数表示出两人的路程，再根据勾股定理列出方程求出未知数的值．

设经过x秒时两人相距85m，
根据题意得（4x）²+（50+3x）²=85²，
去括号得25x²+300x=4725，
即25x²+300x-4725=0，
化简得x²+12x-189=0，
∴（x-9）（x+21）=0，
解得x₁=9，x₂=-21（不符合实际情况，舍去），
当x=9时，4x=36，50+3x=77．
∴当两人相距85m时，甲在O点以东36m处，乙在O点以北77m处．
故当两人相距85米时，甲在O点以东36米处，乙在O点以北77米处．

点评：
本题考点： 一元二次方程的应用；勾股定理．

考点点评： 本题综合考查了方向角，一元二次方程的应用和勾股定理等知识点．要注意的是方向角问题中，南北和西东是垂直的．

63个 1班+2班=45 3班45X5分之二=18

Room 704,Unit 4,A Bldg,Hua Run Apartment,Beijing Road,
Bldg是Building 的缩写.

1、2、4、3、5

解题思路：本题可分别用未知数表示出两人的路程，再根据勾股定理列出方程求出未知数的值．

设经过x秒时两人相距85m，
根据题意得（4x）²+（50+3x）²=85²，
去括号得25x²+300x=4725，
即25x²+300x-4725=0，
化简得x²+12x-189=0，
∴（x-9）（x+21）=0，
解得x₁=9，x₂=-21（不符合实际情况，舍去），
当x=9时，4x=36，50+3x=77．
∴当两人相距85m时，甲在O点以东36m处，乙在O点以北77m处．
故当两人相距85米时，甲在O点以东36米处，乙在O点以北77米处．

点评：
本题考点： 一元二次方程的应用；勾股定理．

考点点评： 本题综合考查了方向角，一元二次方程的应用和勾股定理等知识点．要注意的是方向角问题中，南北和西东是垂直的．

甲乙二人是沿着互相垂直的方向前进的,所以其距离为此直角三角形的斜边长,设X秒后,相距85m,则：
（50+3X）^2+(4x)^2=85^2
2500+300x+9x^2+16x^2=7225
25x^2+300x-4725=0
x^2+12x-189=0
(x+21)(x-9)=0
x1=-21舍去
x2=9
甲的位置是路口东9×4=36米,乙的位置是路口北50+3×9=77米.

yesterday my mother and i went for a walk.then we met a man from the other country.he asked me how to go to the beijing restaurant.l told him walked along the beijing road and turned left at the third crossing.later you will see the restaurant on your right.he was very happy for getting my help.i also felt good for helping him.