non-right angled triangle trigonometry是什么意思?

kingconnie2022-10-04 11:39:541条回答

non-right angled triangle trigonometry是什么意思?
这是一个和数学有关的词

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Analysis.Let a and b be the other two sides of the triangle.From the
conditions of the problem we have c2 = a2 +b2 and c/2=
√
ab ⇔ 3/2c2 =
a2+b2+2ab =(a+b)2 ⇔ 3/2c = a+b.Given a desired ABC let D be
a point on (AC such that CD = CB.In that case,AD = a+b = 3/2c,
and also,since BC = CD,it follows that ∠ADB =45◦.
Construction.From a segment of length c we elementarily construct a
segment AD of length 3/2 c.Wethenconstructaray(DX such that
∠ADX =45◦ and a circle k(A,c) that intersects the ray at point B.
Finally,we construct the perpendicular from B to AD;point C is the
foot of that perpendicular.
Proof.It holds that AB = c,and,since CB = CD,it also holds that AC+
CB = AC +CD = AD = 3/2 c.From this it follows that
√
AC • CB =
c/2.Since BC is perpendicular to AD,it follows that BCA =90◦.Thus
ABC is the desired triangle.
Discussion.Since AB
√2=
√2c> 3/2 c = AD > AB,thecircle k
intersects the ray DX in exactly two points,which correspond to two
symmetric solutions.

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中三数学几何证明题~有图1.ΔABC is a right-angled triangle with∠BAC=90度.A 中三数学几何证明题~有图 1.ΔABC is a right-angled triangle with∠BAC=90度.AF is perpendicular to BC.D is a point on AC such that BD=DC=FC=1.what is the length of AC. 2.InΔABC,∠ACB=120度.CH perpendicular AB.GIVEN THAT CA+AH=HB.FIND∠B 3.AREA OF ΔABK=6,BD:DC=3:5 AND AK;KD=4;5.FIND THE AREA OFΔCDK 4.IN ΔABC,∠C=90度,D AND E ARE POINT ON AB.GIVEN THAT AE=AC,∠DCE=45度.FIND THE SEGMENT HAVING THE SAME LENGTH AS BC 5.the area ofΔABC IS 10.POINT D,E AND F ARE ON AB,BC AND CA RESPECTIVELY SUSH THAT AD=2,DB=3.IF AREA OFΔABE EQUALS AREA OF DBEF WHAT IS THE AREA OFΔABE 6ΔABC IS A RIGHT-ANGLED TRIANGLE WITH∠BCA=90度.THE MEDIAN CM IS PERPENDICULAR TO MEDIAN BN.IF BC =1,WHAT IS THE LENGTH OF BN. boon771年前1: yaba1025 共回答了17个问题 | 采纳率100%

(1).作DE⊥BC于E.∵BD=DC,∴DE是BC的中垂线.
设AD=x.∵AC^2=FC*BC,∴BC=(1+x)^2.
∵AC/BC=(BC/2)/CD,∴(1+x)/(1+x)^2=(1+x)^2/2,
(1+x)^3=2,AC=1+x=立方根2.
(2).延长BA到D,使AD=AC.HB=CA+AH=DA+AH=DH,
∠B=∠D=∠DCA,∠B+∠D+∠DCA+∠ACB=180,∠B=20度.

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