A proton orbits a 1.0-cm-diameter metal ball 1.30 mm above t

花香浓2022-10-04 11:39:541条回答

A proton orbits a 1.0-cm-diameter metal ball 1.30 mm above the surface.The orbital period is 1.60 *10^(-6) s,what is the charge on the ball
翻译:一个质子在一个直径为1.0cm的金属球上方1.3mm处周期运转,质子的周期是1.6*10^(-6)s,问金属球的带电量

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蕴青 共回答了24个问题 | 采纳率91.7%
Q=m4派平方r三方/T平方ke 把数值代入去计算
1年前

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Proton conductivity of the membranes in plane direction (22)
was measured using an electrochemical impedance spectroscopy
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.
英语翻译Activation Energy,Spontaneus Processes,Proton-Transfer R
英语翻译
Activation Energy,Spontaneus Processes,Proton-Transfer Reactions,The Solubility-Product Constant Ksp,Standard Electode Potentials,The s (p,d,f) Orbital,Radius of Atoms,Multiple Bonds,Bond Polarity,Ionic Solids,Fischer projection,aliphatic compound,electrophilic reagent,Cannizzro reaction,halogenated hydrocarbon,hybrid orbital,Lucas reagent,tautomerism,acetic acid
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还有一些,另外我不要软件翻译的,那些不准确。
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Activation Energy,活化能
Spontaneus Processes,自发过程
Proton-Transfer Reactions,质子转移反应
The Solubility-Product Constant Ksp,溶度积常数( ksp )
Standard Electode Potentials,标准电极电势
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Radius of Atoms,原子半径
Multiple Bonds,重键
Bond Polarity,键矩
Ionic Solids,离子晶体
Fischer projection,菲舍尔投影式
aliphatic compound,脂肪族化合物
electrophilic reagent,亲电试剂
Cannizzro reaction 坎尼扎罗反应
halogenated hydrocarbon,卤化烃
hybrid orbital,杂化轨道
Lucas reagent,卢卡斯试剂
tautomerism,互变异构现象
acetic acid 乙酸
coefficient variation,变异系数(CV)
primary standard,基准物质
dissociation constant,解离常数
methyl orange,甲基橙
side reaction副反应系数
coefficient,催化
iodimetry,碘量法
absorptivity,吸光率
bimolecular nucleophilic substitution,双分子亲核取代反应
stereo isomer 立体异构体
网上都能找到,你真懒.
在nature上看到一篇化学论文题目叫Proton fronts on membranes,问这个题目怎么翻译比较好,谢
在nature上看到一篇化学论文题目叫Proton fronts on membranes,问这个题目怎么翻译比较好,谢谢
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先翻译:
问题4.一个质子和一个电子相距遥远,且静止不动.外力(external agent 应该是这个意思吧我不太确定.英语不好泪目.)使电子和质子靠近,而后又使两者静止.关于外力做功哪一种说法是是正确的?
A)做负功.
B)做正功.
C)在这种情况下作功是零,因为质子和电子会自发地来靠近对方,即使没有任何外力作用.
D)上述答案都不对.
选A,做负功.
判断做功的正负基本方法有二:
一,从力的角度看,做功的正负取决于外力和物体的运动方向夹角,若夹角为锐角则正功,夹角为钝角则负功.
二,在受力不明时,应当看能量变化.
某个力做功等于该力对应能量的相反数:正功则表示该力对应能量减小,负功则表示该力对应能量增强(物体下落重力做正功,重力势能减小)
而总能量的变化等于外力做的功:总能量增加,外力作正功;总能量降低,外力作负功.
本题中外力不明,当然选择方法二.在整个过程中,体系内部的能量是动能和电势能,总能量的变化就是外力做的功.
动能:在开始电子和质子静止,最终也是静止,故动能不变;
电势能:由于电子和质子相互吸引,且两者相互靠近,即力方向和位移方向一致,电场力做正功,电势能减小.
故总能量降低,所以外力作负功.
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In[1]:= 2.2*10^6*1.60217653*10^-19
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In[3]:= 3.5247883659999994*10^-13/(9*10^16)
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In[5]:= 3.5247883659999994`*^-13/(3*10^8)
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In[6]:= 1.1749294553333331`*^-21/3.3435835684822224`*^-27
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In[7]:= 351398^2*3.3435835684822224`*^-27
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