第1.2.3牧场的面积依次为3.5.7公顷,三个牧场的草长得一样密,而且长得一样快,有两群牛,第一群牛

lily_chenping2022-10-04 11:39:542条回答

第1.2.3牧场的面积依次为3.5.7公顷,三个牧场的草长得一样密,而且长得一样快,有两群牛,第一群牛
第一、二、三号牧场的面积依次为3公顷、5公顷、7公顷,三个牧场上的草长得一样密,且生长得一样快.有两群牛,第一群牛2天将一号牧场的草吃完,又用5天将二号牧场的草吃完.在这7天里,第二群牛刚好将三号牧场的草吃完.如果第一群牛有15头,那么第二群牛有多少头?

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greens2000 共回答了22个问题 | 采纳率90.9%
答案:15头
设每公顷原有草量为1单位,每公顷每天生长草量为x单位,每头牛每天吃掉草量为y单位.
根据条件,第一群牛2天吃完一号牧场,得到等式:
1*3公顷+x*2天*3公顷=y*15头*2天 ==》3+6x=30y
根据条件,第一群牛又用5天吃完二号牧场,得到等式:
1*5公顷+x*7天*5公顷=y*15头*5天 ==》5+35x=75y 注意,牛吃一号牧场的时候,二号牧场的草仍然在生长,所以,这里草的增长量是按7天计算.
上面2等式联立求解==》x=0.125 y=0.125
设,第二群牛有z头.根据条件,第二群牛7天吃完三号牧场,得到等式:
1*7公顷+x*7天*7公顷=y*z头*7天 ==》7+49x=7yz ==》z=(1+7x)/y 由于x,y值已经求出,故z=15没奥数
1年前
批批 共回答了2个问题 | 采纳率
答案:15头
求解过程如下:
设每公顷原有草量为1单位,每公顷每天生长草量为x单位,每头牛每天吃掉草量为y单位。
根据条件,第一群牛2天吃完一号牧场,得到等式:
1*3公顷+x*2天*3公顷=y*15头*2天 ==》3+6x=30y
根据条件,第一群牛又用5天吃完二号牧场,得到等式:
1*5公顷+x*7天*5公顷=y*15头*5天 ==》5+35x=...
1年前

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牛顿第一定律:
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热力学第二定律
Second law of thermodynamics,about entropy
The total entropy of any isolated thermodynamic system tends to increase over time,approaching a maximum value.
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Newton's Law of Gravity
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