(x分之x-y乘y^2分之x+y)-(x^4y分之x^4-y^4)除(x^2分之x^2+y^2)明天就要交,

jmyhr2022-10-04 11:39:543条回答

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鸭母土 共回答了17个问题 | 采纳率94.1%
(x分之x-y乘y^2分之x+y)-(x^4y分之x^4-y^4)÷(x^2分之x^2+y^2)
=[(x-y)/x *(x+y)/y²-[(x⁴-y⁴)/x⁴y]/[(x²+y²)/x²]
=(x²-y²)/xy²-[(x²+y²)(x²-y²)/x⁴y]/[(x²+y²)/x²]
=(x²-y²)/xy²-(x²-y²)/x²y
=(x²-y²)/xy*(1/y-1/x)
=(x+y)(x-y)/xy*(x-y)/xy
=[(x+y)(x-y)²]/x²y²
1年前
yuanchun119 共回答了1873个问题 | 采纳率
(x-y)/x*(x+y)/y^2-(x^4-y^4)/(x^4y)÷(x^2+y^2)/x^2
=(x-y)(x+y)/(xy^2)-(x^2-y^2)(x^2+y^2)/(x^4y)*x^2/(x^2+y^2)
=(x^2-y^2)/(xy^2)-(x^2-y^2)/(x^2y)
=(x+y)(x-y)^3/(xy)^2
1年前
wangjibuick 共回答了1154个问题 | 采纳率
(x分之x-y乘y^2分之x+y)-(x^4y分之x^4-y^4)除(x^2分之x^2+y^2)
=((x-y)/x *(x+y)/y^2)-((x^2+y^2)/x^2)/((x^4-y^4)/x^4y)
=((x^2-y^2)/xy^2)-((x^2+y^2)/x^2)*(x^4y/(x^2-y^2)(x^2+y^2))
=((x^2-y^2)/xy^2)-((x^2y...
1年前

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