(6/5a³x^4-0.9ax³)÷3/5ax³ (7x²y³-8x&

TAXUS2022-10-04 11:39:541条回答

(6/5a³x^4-0.9ax³)÷3/5ax³ (7x²y³-8x³y²z)÷8x²y²

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(6/5a³x^4-0.9ax³)÷3/5ax³
= 6/5a³x^4 ÷ 3/5ax³ - 0.9ax³ ÷ 3/5ax³
= 2 a^2 x^2 - 1.5
(7x²y³-8x³y²z)÷8x²y²
= 7x²y³ ÷ 8x²y² - 8x³y²z ÷ 8x²y²
= 7/8 y - xz
1年前

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