(1)x^2+y^2-4x+2y+5=0,则x+2y= (2)-3x^2+6xy-3y^2

连云港902022-10-04 11:39:541条回答

(1)x^2+y^2-4x+2y+5=0,则x+2y= (2)-3x^2+6xy-3y^2
(3)因式分解的应用:解方程2x^2=3x

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bssbsb 共回答了14个问题 | 采纳率100%
(1)x²+y²-4x+2y+5=0
x²-4x+4+y²+2y+1=0
(x-2)²+(y+1)²=0
∵(x-2)²≥0,(y+1)²≥0
∴x-2=0,y+1=0
∴x=2,y=-1.
∴x+2y=2+2×(-1)=0
(2)-3x²+6xy-3y²
=-3(x²-2xy+y²)
=-3(x-y)²
(3)2x²=3x
2x²-3x=0
x(2x-3)=0
∴x=0或2x-3=0
∴方程的解为x=0或x=1.5
1年前

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