(x²+1/2xy+1/2y²)-(x²+2/3xy-2y²),其中x=-1/4

醉落夕阳天2022-10-04 11:39:541条回答

(x²+1/2xy+1/2y²)-(x²+2/3xy-2y²),其中x=-1/4,y=1/2

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(x²+1/2xy+1/2y²)-(x²+2/3xy-2y²)
=x²+1/2xy+1/2y²-x²-2/3xy+2y²
=(1-1)x²+(1/2-3/2)xy+(1/2+2)y²
=-xy+5/2y²
=-(-1/4)*1/2+5/2*(1/2)²
=1/8+5/8
=6/8
=3/4
1年前

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