某学校社团对该校高一学生学习出现文理科偏科现象进行调查.随机抽查若干名学生和家长对高一学生学习出现文理科偏科现象的看法,

xingyunshan2022-10-04 11:39:541条回答

某学校社团对该校高一学生学习出现文理科偏科现象进行调查.随机抽查若干名学生和家长对高一学生学习出现文理科偏科现象的看法,统计整理制作了如图的统计图.
(1)求这次调查中的家长人数.
(2)求图乙中表示家长“赞成”的圆心角的度数.
(3)从这次接受调查的学生中,随机抽查一个,恰好是“无所谓”态度的学生的概率是多少?


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Rexy 共回答了17个问题 | 采纳率88.2%
解(1)家长的人数为:40÷40%=100,
(2)表示家长“赞成”圆心角的度数为:
10
100 ×360° =36°;
(3)学生恰好是“无所谓”态度概率是
80
40+80+30 =
8
15 ;
1年前

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某学校社团对该校高一学生学习出现文理科偏科现象进行调查.随机抽查若干名学生和家长对高一学生学习出现文理科偏科现象的看法,
某学校社团对该校高一学生学习出现文理科偏科现象进行调查.随机抽查若干名学生和家长对高一学生学习出现文理科偏科现象的看法,统计整理制作了如图的统计图.
(1)求这次调查中的家长人数.
(2)求图乙中表示家长“赞成”的圆心角的度数.
(3)从这次接受调查的学生中,随机抽查一个,恰好是“无所谓”态度的学生的概率是多少?
数位小子1年前1
longzone 共回答了19个问题 | 采纳率89.5%
解题思路:(1)从扇形统计图中的发现无所谓的家长所占的百分比,条形统计图中无所谓的家长的人数,用人数除以所占的百分比即可求得家长的人数;
(2)赞成的人数除以总人数后乘以圆周角的度数即可得到答案;
(3)用无所谓的学生人数除以总人数即可得到概率.

解(1)家长的人数为:40÷40%=100,
(2)表示家长“赞成”圆心角的度数为:[10/100×360°=36°;
(3)学生恰好是“无所谓”态度概率是
80
40+80+30]=[8/15];

点评:
本题考点: 条形统计图;扇形统计图;概率公式.

考点点评: 本题考查了扇形统计图、条形统计图及概率公式的知识,解题的关键是从两种统计图中整理出解题的有关信息;

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