log2x^2=log2(根号2-1)-log2(根号2+1),求x+1/x

log2(x²)=log2[(√2-1)/(√2+1)]
log2(x²)=log2(√2-1)²
所以x²=(√2-1)²
x=±(√2-1)
x=√2-1
则1/x=√2+1
x+1/x=2√2
x=-√2+1
则1/x=-√2-1
x+1/x=-2√2
所以x+1/x=±2√2

x+1/x = t,求出x,代入等到式中，求得t