let t be an equilateral triangle whose sides are of length 1

风95272022-10-04 11:39:541条回答

let t be an equilateral triangle whose sides are of length 1 unit .show that if any five points are

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gg人雄起 共回答了17个问题 | 采纳率94.1%
有单位长度的等边三角形,显示其中...的任意5个点.这根本没有写完嘛
1年前

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let t be an equilateral triangle whose sides are of length 1
let t be an equilateral triangle whose sides are of length 1 unit .show that if any five points are chosen lying on or insides the triangle ,then two of them must be no more than 1/2 unit
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一个边长为1的正三角形,在这个三角形边上或者内部任取2个点,是否这2个点的距离都不会大于1/2
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(B) 8
(C) 11
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the length of arc ABC 究竟指什么?是三角形ABC的周长么?可我用周长做,2,明显选B,为什么正确答案是C?
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.Arc=弧度
因为是equilateral triangle(等边三角形),arc AB,BC,CA的长度必须是相等的.也就是说,Arc ABC的长度是24的话,这三段Arc分别是12,那这个圆的周长就是36.
周长的公式:P= πd
d是直径,所以就是P÷π,周长除以 π而已.
36÷3.14=11.46.最接近的数字是11.所以是C.
恩.结论就是,基本公式要背熟
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