江湖救急!已知a、b、c是不全相等的实数,求证：（a2+1)(b2+1)(c2+1)>8abc2是平方

He is the man who made the mistake.照着弄就行了

.当分母为零时无意义,所以x^2-2x+m不可能等于零,即函数y=x^2-2x+m与x轴无交点,b^2-4ac

5.(1.)设出5个点的坐标
A点与BCDE的坐标之差有4种形式（奇偶）,（偶奇）,（奇奇）,（偶偶）
若为（偶偶）,则显然中心（即中点）为整点
若都不是（偶偶）,则BCDE中必有两点坐标与A之差属于同一类,则这两点的坐标之差为（偶偶）.
命题得证
(2.),(3.)略复杂一点,用坐标奇偶法讨论使用抽屉原理也可与做出来
第一题没看懂
2.两个直角三角形明显只能放在一起,拼成一个边长为2的正方形.所以不需要讨论直角三角形,只需讨论两种正方形拼法,最后用直角三角形替换大正方形看还有多少种就行了.
但是貌似N还要分奇偶,比较复杂.本人没有信心做下去了
第三题太复杂了
第四题有27个空格,是只放一种颜色的棋子吗?
如果是的,那就是2^27次方种（每个空格放或不放）
如果是黑白2色,那就是3^27次方种（每个空格3种选择）

这是我第一次完整的读完一篇现代诗文，也是第一次读冰心奶奶的作品，更是第一次读到《繁星》这篇动人得巨著。读完之后有一种从未有过的感觉在我的脑子里飘动。可想而知《繁星》这本书有多么意蕴深刻，饱含的哲理多么耐人寻味，多么能令人回味无穷…… 《繁星》这本书是我国著名的文学家，我从小就听说过——冰心写的。以前妈妈常给我读她写的诗文，但因我那是太小，听不懂，总是三心二意，但现在我以是快上六年级的学生了，这不我...

1.A 2.A 3.DIDN'T 4.29 Twenty-nine 32 thirty-two 40 forty 56 fifty-six 94 ninety-four 5.A 6.D 7.A 8.B 9.invitation swimming may stays 10.A

z=a+bi
则a²+b²=5²
(3+4i)(a+bi)
=(3a-4b)+(4a+3b)i
在第二、四象限的角平分线上
则x+y=0
即3a-4b+4a+3b=0
b=7a
a²+b²=5²
所以50a²=25
a=±√2/2
b=7a
所以z=√2/2+7√2i/2或-√2/2-7√2i/2

A：the suspect
B:the policeman
A：why take me here?I hate you!
B:You know why.
A：I know?!You sucker~
B:Dare you!Let me give you some color to see see.
A:Ha,come on.I like Kungfu,I like to be beaten too.
B:Look what a bastard you are !
A：I am a good man right before you take me here!
B:Really?So you think I got wrong of you?
A：You can say it again.
B:OK,I am tired questioning you.You are so disgusting.
A：If I am disgusting,you are a pile of shit before me!
B:Guards,come!Take this sucker to the cell and give him a f**k!
A：Hahaha~Am I afraid of that?You know what,I am a gay!
B:Oh shit!What a terrible day~

ich bitte Sie um die Verzeihung,dass ich Ihnen so eine Ungünstigkeit gebraht habe,die von meiner schuld ursacht wurde.auf jeden fall freue ich mich sehr herzlich auf eine schöne zusammenarbeit.意思是：对于我由于自己失误给您带来不便这件事,我请求你原谅.无论如何我真诚的希望我们合作愉快.
读法的话：yixi bite sei um du fer才ong ,dasi ich yinen so aine onggeyunsitixikaite gebehahete habe,di feng mai呢 shude uesahe特.urde.aof yeden fa fehaoe yixi mixi aof aine zusamen啊r百特.
我去.费劲死我了.我写的是拼音.你按照拼音法发就行.

I believe I have tried my best to learn English.Because I show interest in English so it is not so hard for me to do so.
Usually I will do some preparing before class like reading the text or looking up new words in the dictionary.If some writers get my interest I will search information about them in the internet.While having classes,of cause I will listen to teacher carefully and take some notes if necessary.Sometimes teacher will talk about something I’ve never heard.After class review the text is what I usually do and I think this help me to learn it better.
没控制好,108,楼主看看可以去掉一些个字词句的,有问题直说~

#include #include #include #include #include #define CROSSRU 0xbf /*右上角点*/ #define CROSSLU 0xda /*左上角点*/ #define CROSSLD 0xc0 /*左下角点*/ #define CROSSRD 0xd9 /*右下角点*/ #define CROSSL 0xc3 /*左边*/ #define CROSSR 0xb4 /*右边*/ #define CROSSU 0xc2 /*上边*/ #define CROSSD 0xc1 /*下边*/ #define CROSS 0xc5 /*十字交叉点*/ /*定义棋盘左上角点在屏幕上的位置*/ #define MAPXOFT 5 #define MAPYOFT 2 /*定义1号玩家的操作键键码*/ #define PLAY1UP 0x1157/*上移--'W'*/ #define PLAY1DOWN 0x1f53/*下移--'S'*/ #define PLAY1LEFT 0x1e41/*左移--'A'*/ #define PLAY1RIGHT 0x2044/*右移--'D'*/ #define PLAY1DO 0x3920/*落子--空格键*/ /*定义2号玩家的操作键键码*/ #define PLAY2UP 0x4800/*上移--方向键up*/ #define PLAY2DOWN 0x5000/*下移--方向键down*/ #define PLAY2LEFT 0x4b00/*左移--方向键left*/ #define PLAY2RIGHT 0x4d00/*右移--方向键right*/ #define PLAY2DO 0x1c0d/*落子--回车键Enter*/ /*若想在游戏中途退出, 可按 Esc 键*/ #define ESCAPE 0x011b /*定义棋盘上交叉点的状态, 即该点有无棋子 */ /*若有棋子, 还应能指出是哪个玩家的棋子 */ #define CHESSNULL 0 /*没有棋子*/ #define CHESS1 'O'/*一号玩家的棋子*/ #define CHESS2 'X'/*二号玩家的棋子*/ /*定义按键类别*/ #define KEYEXIT 0/*退出键*/ #define KEYFALLCHESS 1/*落子键*/ #define KEYMOVECURSOR 2/*光标移动键*/ #define KEYINVALID 3/*无效键*/ /*定义符号常量: 真, 假 --- 真为1, 假为0 */ #define TRUE 1 #define FALSE 0 /**********************************************************/ /* 定义数据结构 */ /*棋盘交叉点坐标的数据结构*/ struct point { int x,y; }; /**********************************************************/ /*自定义函数原型说明 */ void Init(void); int GetKey(void); int CheckKey(int press); int ChangeOrder(void); int ChessGo(int Order,struct point Cursor); void DoError(void); void DoOK(void); void DoWin(int Order); void MoveCursor(int Order,int press); void DrawCross(int x,int y); void DrawMap(void); int JudgeWin(int Order,struct point Cursor); int JudgeWinLine(int Order,struct point Cursor,int direction); void ShowOrderMsg(int Order); void EndGame(void); /**********************************************************/ /**********************************************************/ /* 定义全局变量 */ int gPlayOrder; /*指示当前行棋方 */ struct point gCursor; /*光标在棋盘上的位置 */ char gChessBoard[19][19];/*用于记录棋盘上各点的状态*/ /**********************************************************/ /**********************************************************/ /*主函数*/ void main() { int press; int bOutWhile=FALSE;/*退出循环标志*/ printf("Welcome www.***.com"); Init();/*初始化图象，数据*/ while(1) { press=GetKey();/*获取用户的按键值*/ switch(CheckKey(press))/*判断按键类别*/ { /*是退出键*/ case KEYEXIT: clrscr();/*清屏*/ bOutWhile = TRUE; break; /*是落子键*/ case KEYFALLCHESS: if(ChessGo(gPlayOrder,gCursor)==FALSE)/*走棋*/ DoError();/*落子错误*/ else { DoOK();/*落子正确*/ /*如果当前行棋方赢棋*/ if(JudgeWin(gPlayOrder,gCursor)==TRUE) { DoWin(gPlayOrder); bOutWhile = TRUE;/*退出循环标志置为真*/ } /*否则*/ else /*交换行棋方*/ ChangeOrder(); ShowOrderMsg(gPlayOrder); } break; /*是光标移动键*/ case KEYMOVECURSOR: MoveCursor(gPlayOrder,press); break; /*是无效键*/ case KEYINVALID: break; } if(bOutWhile==TRUE) break; } /*游戏结束*/ EndGame(); } /**********************************************************/ /*界面初始化，数据初始化*/ void Init(void) { int i,j; char *Msg[]= { "Player1 key:", " UP----w", " DOWN--s", " LEFT--a", " RIGHT-d", " DO----space", "", "Player2 key:", " UP----up", " DOWN--down", " LEFT--left", " RIGHT-right", " DO----ENTER", "", "exit game:", " ESC", NULL, }; /* 先手方为1号玩家 */ gPlayOrder = CHESS1; /* 棋盘数据清零, 即棋盘上各点开始的时候都没有棋子 */ for(i=0;i<19;i++) for(j=0;j<19;j++) gChessBoard[j]=CHESSNULL; /*光标初始位置*/ gCursor.x=gCursor.y=0; /*画棋盘*/ textmode(C40); DrawMap(); /*显示操作键说明*/ i=0; textcolor(BROWN); while(Msg!=NULL) { gotoxy(25,3+i); cputs(Msg); i++; } /*显示当前行棋方*/ ShowOrderMsg(gPlayOrder); /*光标移至棋盘的左上角点处*/ gotoxy(gCursor.x+MAPXOFT,gCursor.y+MAPYOFT); } /*画棋盘*/ void DrawMap(void) { int i,j; clrscr(); for(i=0;i<19;i++) for(j=0;j<19;j++) DrawCross(i,j); } /*画棋盘上的交叉点*/ void DrawCross(int x,int y) { gotoxy(x+MAPXOFT,y+MAPYOFT); /*交叉点上是一号玩家的棋子*/ if(gChessBoard[x][y]==CHESS1) { textcolor(LIGHTBLUE); putch(CHESS1); return; } /*交叉点上是二号玩家的棋子*/ if(gChessBoard[x][y]==CHESS2) { textcolor(LIGHTBLUE); putch(CHESS2); return; } textcolor(GREEN); /*左上角交叉点*/ if(x==0&&y==0) { putch(CROSSLU); return; } /*左下角交叉点*/ if(x==0&&y==18) { putch(CROSSLD); return; } /*右上角交叉点*/ if(x==18&&y==0) { putch(CROSSRU); return; } /*右下角交叉点*/ if(x==18&&y==18) { putch(CROSSRD); return; } /*左边界交叉点*/ if(x==0) { putch(CROSSL); return; } /*右边界交叉点*/ if(x==18) { putch(CROSSR); return; } /*上边界交叉点*/ if(y==0) { putch(CROSSU); return; } /*下边界交叉点*/ if(y==18) { putch(CROSSD); return; } /*棋盘中间的交叉点*/ putch(CROSS); } /*交换行棋方*/ int ChangeOrder(void) { if(gPlayOrder==CHESS1) gPlayOrder=CHESS2; else gPlayOrder=CHESS1; return(gPlayOrder); } /*获取按键值*/ int GetKey(void) { char lowbyte; int press; while (bioskey(1) == 0) ;/*如果用户没有按键，空循环*/ press=bioskey(0); lowbyte=press&0xff; press=press&0xff00 + toupper(lowbyte); return(press); } /*落子错误处理*/ void DoError(void) { sound(1200); delay(50); nosound(); } /*赢棋处理*/ void DoWin(int Order) { sound(1500);delay(100); sound(0); delay(50); sound(800); delay(100); sound(0); delay(50); sound(1500);delay(100); sound(0); delay(50); sound(800); delay(100); sound(0); delay(50); nosound(); textcolor(RED+BLINK); gotoxy(25,20); if(Order==CHESS1) cputs("PLAYER1 WIN!"); else cputs("PLAYER2 WIN!"); gotoxy(25,21); cputs(" \<^+^>/"); getch(); } /*走棋*/ int ChessGo(int Order,struct point Cursor) { /*判断交叉点上有无棋子*/ if(gChessBoard[Cursor.x][Cursor.y]==CHESSNULL) { /*若没有棋子, 则可以落子*/ gotoxy(Cursor.x+MAPXOFT,Cursor.y+MAPYOFT); textcolor(LIGHTBLUE); putch(Order); gotoxy(Cursor.x+MAPXOFT,Cursor.y+MAPYOFT); gChessBoard[Cursor.x][Cursor.y]=Order; return TRUE; } else return FALSE; } /*判断当前行棋方落子后是否赢棋*/ int JudgeWin(int Order,struct point Cursor) { int i; for(i=0;i<4;i++) /*判断在指定方向上是否有连续5个行棋方的棋子*/ if(JudgeWinLine(Order,Cursor,i)) return TRUE; return FALSE; } /*判断在指定方向上是否有连续5个行棋方的棋子*/ int JudgeWinLine(int Order,struct point Cursor,int direction) { int i; struct point pos,dpos; const int testnum = 5; int count; switch(direction) { case 0:/*在水平方向*/ pos.x=Cursor.x-(testnum-1); pos.y=Cursor.y; dpos.x=1; dpos.y=0; break; case 1:/*在垂直方向*/ pos.x=Cursor.x; pos.y=Cursor.y-(testnum-1); dpos.x=0; dpos.y=1; break; case 2:/*在左下至右上的斜方向*/ pos.x=Cursor.x-(testnum-1); pos.y=Cursor.y+(testnum-1); dpos.x=1; dpos.y=-1; break; case 3:/*在左上至右下的斜方向*/ pos.x=Cursor.x-(testnum-1); pos.y=Cursor.y-(testnum-1); dpos.x=1; dpos.y=1; break; } count=0; for(i=0;i=0&&pos.x<=18&&pos.y>=0&&pos.y<=18) { if(gChessBoard[pos.x][pos.y]==Order) { count++; if(count>=testnum) return TRUE; } else count=0; } pos.x+=dpos.x; pos.y+=dpos.y; } return FALSE; } /*移动光标*/ void MoveCursor(int Order,int press) { switch(press) { case PLAY1UP: if(Order==CHESS1&&gCursor.y>0) gCursor.y--; break; case PLAY1DOWN: if(Order==CHESS1&&gCursor.y<18) gCursor.y++; break; case PLAY1LEFT: if(Order==CHESS1&&gCursor.x>0) gCursor.x--; break; case PLAY1RIGHT: if(Order==CHESS1&&gCursor.x<18) gCursor.x++; break; case PLAY2UP: if(Order==CHESS2&&gCursor.y>0) gCursor.y--; break; case PLAY2DOWN: if(Order==CHESS2&&gCursor.y<18) gCursor.y++; break; case PLAY2LEFT: if(Order==CHESS2&&gCursor.x>0) gCursor.x--; break; case PLAY2RIGHT: if(Order==CHESS2&&gCursor.x<18) gCursor.x++; break; } gotoxy(gCursor.x+MAPXOFT,gC

1.
衣：依,铱,袅
兑：锐,税,说
舟：盘
麻：嘛
舌：适
3.
名--〉各
厌--〉庆

A

都是过去时,选1

巴黎圣母院,雨果
鲁迅的《野草》
泰戈尔的《吉檀迦利》
《普希金诗选》·(俄)普希金

骏马一跨跃,也不足十步远；劣马拉车走十天,（也能走得很远,）它的成功就在于不停地走.（如果）刻几下就停下来了,（那么）腐烂的木头也刻不断.（如果）不停地刻下去,（那么）金石也能雕刻成功.

先运用积化和差公式
sinx*sin3x*sin2x=(cos2x-cos4x)*sin2x/2
cosx*cos3x*cos2x=(cos2x+cos4x)* cos2x/2
相加化简
sinx*sin3x*sin2x+ cosx*cos3x*cos2x=（cos2x+cos4x*cos2x）/2
=cos2x(1+2cos22x-1)/2
=cos32x
最后的式子= cos2x+sin2x
=（根号2）*sin(2x+∏/4)
所以最小值是负的根号2

你所说的两个圆的方程可以化为
(x+3)^2+y^2=13
(x+3)^2+y^2=37
这两个圆圆心相同,半径不等,应该会组成同心环.不存在交点
你看是不是问题发错了

1. 过点A做MB平行线,过点B做MA,交于点P,联结MP,交AB于O
向量MP=向量MA+MB么
又因M是ABC重心,有MO=1/2CM
MO=1/2MP
所以CM=MA+MB 即MA+MB+mc=0
2..如果没理解错的话.答案是 1
把更号里的那个分式上下同乘cosX 就可以了
3..应该有几种情况吧,画画图就知道了,一个面积是1/2,一个市1/4,不知道还有么有其他
情况
4..过圆心O做任意直径AB,圆周上任取一点C,联结OC
OA=OB=OC
貌似直角三角形就有这样一个定理吧?

1.B截止目前时间点,我第一次享用到,现在完成
2.C我本应写下来
3.A固定说法
4.A A特地,专程 B特别的 C特别是
5.B谓语动词依据one person

3121 主语是第一人称的话用动词原形,比如i 和we作主语,解释成"我/我们/他们怎样"这一类的就是第一人称.相反,像是"她/他/它怎样"就是第三人称单数形式,加s或es或用过去式也是可以的.举例:第一人称:I/we /They look at the picture.第三人称:She/He looks at me.你的前三道题都是这个问题.最后一道题是magaziner,是复数形式,所以用them,要是题中是magazine的话就选it了:-) 我很够意思吧!

π=pq-c=14q-0.01qq-20-4q-0.01qq
=-20+10q-0.02qq
π‘=10-0.04q=0
q=10/0.04=1000/4=250
产量为250时候,可使利润达到最大
最大利润是πmax=-20+2500-0.02*250*250=1230元
这是微观经济学的题目

做DG‖AE,DG交BC于G
∵DG‖AE
∴∠DGB=∠ACB
又∵∠CGD=180°-∠DGB,∠BCE=180°-∠ACB
∴∠CGD=∠BCE
∵∠B=∠ACB,∠DGB=∠ACB
∴∠B=∠DGB
∴BD=GD
又∵BD=CE
∴GD=CE
又∵∠BFD=∠CFE
∴ΔDFG≌ΔEFC
∴DF=EF

弧长近似等于振幅

DESTIBY
理解你的急切心情,这是一篇难得的演讲稿,从健康的现代定义开始,然后讲到保持健康的重要性,最后提倡健康的生活方式,并且给出建议.结构清晰紧凑,希望能帮得上你忙.字数的删减你可以通过最后提倡的建议做适当的修改.
Healthy Living
Health,by definition,is a state of physical,mental and social well being.It implies the absence of infirmity or disease,but their mere absence does not define health.Earning and maintaining health is an active process.Good health is a result of proper nutrition,regular exercise,health care and hygiene.One of the most important factors determining the mental health of an individual is his/her happiness quotient.Hence,effective stress management forms a vital factor in remaining healthy.
Why is it Important to be Healthy?
Human beings are the most important assets of a nation.It is people who drive the world,it is we who make the world go round.The absence of health can make the world come to a standstill.Do I seem to be exaggerating?I am not.The absence of health can actually mean passivity,unhappiness and gloom.Would anyone like to live in a somber atmosphere?Would we be able to thrive in an unhealthy atmosphere?The true definition of health brings out the real essence of a healthy life.The concept of being healthy is a composition of different facets of life.It includes physical well-being,which can be brought about by a healthy diet and exercise; it constitutes the maintenance of health through proper precaution and cures for physical ailments.The conveniently ignored facet of being healthy is the mental well-being.One's happiness and positivism are highly influential in the maintenance of one's health.
Healthy Living Tips:Living a Healthy Lifestyle
Here are a few healthy living tips.They work for me.Maybe they will work for you.You should always find your own path to living the healthy lifestyle.
1.Everything should be done in moderation – eating,working,resting,playing,maintaining hobbies,socializing,and so on.
2.You should take stock of how you spend your day,so you can reschedule your time,concentrate on important chores,cut down on the inconsequential,and thereby suffer less stress.
3.Don't take on more work or personal responsibilities than you can realistically handle.
4.Do what you love.The money will usually follow.
5.Try to be less materialistic and keep your life simple.It is really unnecessary to keep up with the Joneses.Why buy a car if you can avail of public transport?Why own a cell-phone when you don't really need one?Why beat yourself up trying to upgrade to the latest software when the old one serves you just fine?
6.Pay all your bills regularly and on time.Never take a loan if you're not sure about meeting the monthly payments.Live within your means.
7.You should sleep for at least eight hours every night.A siesta in the afternoon,if possible,is also a good idea and certainly refreshing for your brain.
8.Control your mind.What you think and how you think affects your general well-being.Refuse to entertain negative or self-derogatory thoughts and emotions.This will require practice,especially if you have fallen into the habit of seeing the glass half-empty.
9.Cultivate your spiritual side.You don't have to turn religious and burn candles at public altars,but keeping in touch with your intuition and your inner self is important.
10.Go for comfort over fashion any day.
11.Eat well and healthy.Learn to cook well.Try new recipes.Make meals interesting and fun.
12.Exercise regularly.Go for a short run every morning.Do Yoga.Exercise your eyes regularly,especially if you spend a lot of time in front of the computer.If you have to run errands around the neighborhood,walk or cycle around.Walk up stairways instead of taking the lift.
13.Go for regular medical check-ups.If you have health problems,talk to your doctor and discuss all the options that are available for you.Get a second,third,fourth opinion.Research on the Internet.Don't panic,lose hope,or give up easily.
14.Read books,magazines,newspapers.Be aware of what is going on around you,locally,nationally,and internationally.Try to learn at least one thing new every day.
15.Don't take yourself too seriously.Learn to laugh at yourself.
16.Don't indulge in malicious gossip.
17.Pay attention to the thing that
you're doing at any given moment,and do it well.

June 6,2006
Dear students,
The English Summer Camp will be held in the school hall from July 29 to August 1. Many interesting activities are waiting for you to join in.
During the camp,you can give a lecture and have a debate. Besides,the students who do well in English study will talk about their experience. There is also an English party between teachers and students. In the end,you’11 have a chance to visit the City of Tianjin.
Everyone is welcome to take an active part in it. Don't forget to tell us what you think of the camp in your diary. Students’ Union

Dear friends,
Today we are having a party to honor our friend Peter, who is returning to his own country with his parents. How time flies! It was a year since he came to our school. During this period, we have helped each other and thus have become good friends. What's more, many of us have become more interested in English and have made great progress in it.
We all hope that when he returns to his homeland, he will get in touch with us as often as possible. We also hope that he will come to China again some day. Good luck, Tom. And good luck to your family. May you have a pleasant trip home! Thank you.

1.两边同时平方,然后往下做就可以了
x²-2x+10
x2
2.第二题分别乘出来就可以了
（6+2x）(x²+1)>(12-3x)(x²+11)

快车追上时跑了 24*6/60＝2.4千米
中车追上时跑了 20*10/60＝10/3千米
这4分钟里自行车跑了 10/3-2.4＝14/15千米
自行车的时速 （14/15）/（4/60）＝14千米/每小时
3辆车追赶前,自行车先行了 2.4-14*0.1=1千米
慢车追上自行车时自行车跑了14*12/60+1=3.8千米
慢车时速 3.8/（12/60）＝19千米每小时

单选14134 14333 11134
完形24231 33221 42213 43124
阅读4233 1134 2112 1324 2413

1.是的 2.氧化钠不需加热,但是通常情况下,氧化钠与水反应更快,所以若把氧化钠放在空气中它会先生成氢氧化钠,再由氢氧化钠与二氧化碳反应,
氧化钠也可直接与二氧化碳反应Na2O+CO2=Na2CO3 ,后者需高温 3.通过量的二氧化碳 4.碳酸钠 无水 5.反应物之一能电离出离子,且满足复分解反应的条件、氧化还原反应的条件等,即要客观的能发生化学反应,反应能发生.6.三价铁的氧化性远强于四价硅,是伴随着的,co当然可以还原SiO2 .7.硅是原子晶体,硅与硅的化学键能大 8.氢氧化钾、碳酸钠、碳酸钾、硅酸钠、酒石酸钠等 9.1+a(n+1)=（an+1)∧2 令bn=.1+a(n+1) b1=3 b2=3∧2 b3∧4.
bn=3∧2的（n-1) 然后自己在变形即可得答案.

{ak+bk}是以a1+b1=-4为首项的等差数列
所以Sk+Sk'=k(-4+ak+bk)/2=0
所以ak+bk=4

Please don't torture me,I'm really annoying

如果工资额刚好比3500元高1500元,那么应缴：1500*0.3=45元
如果工资额刚好比5000元高3000元,那么应缴：3000*0.1=300元,
很显然工资面议超过8000元,那么总税额155-45=110元,即超出5000元的部分按0.1缴了110元.
110/0.1=1100元
即总工资为3500+1500+1100=6100元.
我说清楚了吗?

有 新东方有 词以类记 我买的是托福词汇的词以类记,别的等级英语也有好像~去新东方的大愚书店,或者别的书店,或者网上都应该有卖的.

{[(10/2)*(10/2)*3.14]/2}*4*999/10000
半径的平方*圆周率=圆的面积；因为是半圆 所以除以2；
有4个半圆 所以 *4 ；有999个砖 就*999； 把平方厘米 换成平方米 所以 除以10000
结果约=0.156平方米
题上说的25厘米 是表示 你画4个半圆 将没有交点
就不会有重复被换掉的砖

=(a-3b)(a+3b)+2a-6b
已知a+3b=-2
=-2(a-3b)+2a-6b
=0

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1:Price List 2:general hydraulic 3:Oil back open 4:Thai massage 5:Oil foot 6:Crystal mud foot 7:milk petal foot 8:Chinese medicine foot 9:body massage Meridian 10:Qian feet 11:ear candling 12:Cupping 13:14-ear:Package 15:foot 16:Packages limit every Monday to Friday before 18:00
绝对正确

我有公式定理大全,你要吗?

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写作主体
逻辑思维 ：人们在认识过程中借助于概念、判断、推理等思维形式能动地反映客观现实的理性认识过程,又称理论思维.它是作为对认识着的思维及其结构以及起作用的规律的分析而产生和发展起来的.只有经过逻辑思维,人们才能达到对具体对象本质规定的把握,进而认识客观世界.它是人的认识的高级阶段,即理性认识阶段.
观察 ：细察事物的现象、动向
结构与功能相适应规律
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1.FlexEfficiency * 50
2.柔性热发电
3.地方上的“灵活性”的价值,包括它的经济评价
未来一代增加
4.重要的是如何在燃气轮机和联合循环热发电的灵活性和可以如何帮助变异?
5.如何将燃气轮机和联合循环发电是不同的,特别是在对他们将需要更多的操作时数?
6.你怎么看变化和电网的变化和影响更多的可再生能源间歇性的介绍?

Never judge a man by his appearance
A new classmate joins our class this semester.At the beginning, I don't really like him very much.My friend tells me that he is very rude and selfish.
One day, what happened changed my idea. I was sick in hospital and bored in bed,suddenly someone called my name.It is him.He has been in the hospital for several days and taken care of me.
After that, I know a saying:"Never judge a man by his appearance."

已知弧长C=35,弦长L=20.求半径R是多少?
Rn+1=(1+(L-2*Rn*SIN(C/(2*Rn)))/(L-C*COS(C/(2*Rn))))*Rn
R0=10
R1=10.122
R2=10.125
R3=10.125
R=10.125

CDBAD
BCAAA
BCDAB
ABCA
希望楼主以后把正确答案发出来

什么主题

(1)因y=kx+b平行于直线y=-3x+4,故斜率相等,k=-3
又因为与直线y=2x-6的交点在x轴,即y=0,故交点为(3,0)
将(3,0)代入y=-3x+b,得0=-9+b,故b=9
解析式y=-3x+9
(2)根据已知x增加2时,y减少3,可知斜率=△y/△x=-3/2
所以k=-3/2