(8/9xy^2-4/3x^2y)(9/4x^2y^2)+3x^2y^2x^2y

zlqEla2022-10-04 11:39:541条回答

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凡世尘缘共回答了19个问题 | 采纳率100%: (8/9xy^2-4/3x^2y)*(9/4x^2y^2)+3x^2y^2*x^2y
=2x^3y^4-3x^4y^3+3x^4y^3
=2x^3y^4; 1年前

7m(4m^2 ×p)^2/7m^2 [x(x^2 y^2-xy)-y(x^2-x^3y)]/3x^2y (2x+y+z 7m(4m^2 ×p)^2/7m^2 [x(x^2 y^2-xy)-y(x^2-x^3y)]/3x^2y (2x+y+z)(2x-y-z)(2x-y-3)^2 (x+y+1)(x+y-1) 爱听故事的小孩1年前1: 皮拖共回答了19个问题 | 采纳率89.5%

1、7m(4m^2·p)^2=7m*4^2*(m^2)^2*p^2 =7m*4^2*m^4*p^2 =7*16m*m^4*p^2 =112m^5*p^2所以7m(4m^2·p)^2÷7m^2=112m^5*p^2÷7m^2=16m^3p^2
2、[x(x^2y^2-xy)-y(x^2-x^3y)]/(3x^2y)={x[xy(xy-1)]-y[x²(1-xy)]}/(3x²y)=[x²y(xy-1)-yx²(1-xy)]/(3x²y)=[x²y(xy-1)+yx²(xy-1)]/(3x²y)=[x²y(xy-1)+x²y(xy-1)]/(3x²y)=[2x²y(xy-1)]/(3x²y)=[2(xy-1)]/3
3、(2x+y+z)(2x-y-z)=(2x+y+z)[2x-(y+z)]=(2x)^2-(y+z)^2=4x^2-(y^2+2yz+z^2)=4x^2-y^2-2yz-z^2

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计算[x(x^2y^2-xy)-y(x^2-x^3y)]/3x^2y 计算[x(x^2y^2-xy)-y(x^2-x^3y)]/3x^2y 如题 我性狂野1年前2: 一滴水5 共回答了16个问题 | 采纳率100%

[x(x^2y^2-xy)-y(x^2-x^3y)]/3x^2y
=(x^3y^2-x^2y-x^2y+x^3y^2)/3x^2y
=(2x^3y^2-2x^2y)/3x^2y
=2x^3y^2/3x^2y-2x^2y/3x^2y
=(2xy-2)/3

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(8/9xy^2-4/3x^2y)*(9/4x^2y^2)+3x^2y^2*x^2y