(log32+log23)^2-log32/log23-log23/log32

love伊念2022-10-04 11:39:541条回答

(log32+log23)^2-log32/log23-log23/log32
log32就是3是底数,2是真数

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c8328759 共回答了13个问题 | 采纳率92.3%
[log3(2)+log2(3)]^2-log3(2)/log2(3)-log2(3)/log3(2)
=[log3(2)+log2(3)]^2-[1/log2(3)]/log2(3)-[1/log3(2)]/log3(2)
=[1/log2(3)+1/log3(2)]^2-[1/log2(3)]^2-[1/log3(2)]^2
=2/[log2(3)*log3(2)]
=2
1年前

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