y1=ax1^2+bx1+c,y2=ax2^2+bx2+c,y3=ax3^2+bx3+c,已知x1,x2,x3,y1,y

xmkunpeng2022-10-04 11:39:541条回答

y1=ax1^2+bx1+c,y2=ax2^2+bx2+c,y3=ax3^2+bx3+c,已知x1,x2,x3,y1,y2,y3,求a,b,c的表达式

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heuca1979 共回答了15个问题 | 采纳率93.3%: a=y1/[(x1-x2)(x1-x3)]+y2/[(x2-x1)(x2-x3)]+y3/[(x3-x1)(x3-x2)]
b=-y1(x2+x3)/[(x1-x2)(x1-x3)]-y2(x1+x3)/[(x2-x1)(x2-x3)]-y3(x1+x2)/[(x3-x1)(x3-x2)]
c=y1x2x3/[(x1-x2)(x1-x3)]+y2x1x3/[(x2-x1)(x2-x3)]+y3x1x2/[(x3-x1)(x3-x2)]
都是轮换对称的式子.; 1年前

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