(am+bn)^2+(an-bm)^2=?

queenst2022-10-04 11:39:542条回答

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飞歌传输共回答了23个问题 | 采纳率78.3%: (am+bn)^2+(an-bm)^2
=(am)^2+2abmn+(bn)^2+(bm)^2-2abmn+(an)^2
=(am)^2+(bn)^2+(bm)^2+(an)^2
=a^2(m^2+n^2)+b^2(m^2+n^2)
=(a^2+b^2)(m^2+n^2); 1年前

桥影共回答了8个问题 | 采纳率: (am+bn)^2+(an-bm)^2=a^2m^2+2abmn+b^2n^2+a^2n^2-2abmn+b^2m^2
=(a^2+b^2)m^2+(a^2+b^2)n^2
=(a^2+b^2)(m^2+n^2); 1年前

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