(2013•渭源县模拟)菱形OABC在平面直角坐标系中的位置如图所示,∠AOC=45°,OC=22,则点B的坐标为(22

24681aa2022-10-04 11:39:541条回答

(2013•渭源县模拟)菱形OABC在平面直角坐标系中的位置如图所示,∠AOC=45°,OC=2
2
,则点B的坐标为
(2
2
+2,2)
(2
2
+2,2)

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共1条回复
维他命D1 共回答了21个问题 | 采纳率85.7%
解题思路:过C作CE⊥OA,根据“∠AOC=45°,OC=2
2
”可以求出CE、OE的长,点B的坐标便不难求出.

过C作CE⊥OA于E,

∵∠AOC=45°,OC=2
2,
∴OE=OCcos45°=
2,
CE=OCsin45°=2,
∴点B的坐标为(2
2+2,2).

点评:
本题考点: 菱形的性质;坐标与图形性质;特殊角的三角函数值.

考点点评: 作辅助线构造直角三角形,根据三角函数求出C点坐标是解本题的关键.

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(2011•渭源县) 解方程或比例.
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解方程或比例.
[3/5]X+0.8=5.6

1.4:x=1:0.75

1+25%x=3.
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(2)先根据比例的基本性质,把原式转化为x=1.4×0.75,再化简求解,
(3)根据等式的性质,在方程两边同时减1,再除以0.25求解.

(1)[3/5]X+0.8=5.6,
[3/5]X+0.8-0.8=5.6-0.8,
[3/5]X×[5/3]=4.8×[5/3],
X=8;

(2)1.4:x=1:0.75,
x=1.4×0.75,
x=1.05;

(3)1+25%x=3,
1+25%x-1=3-1,
0.25x÷0.25=2÷0.25,
x=8.

点评:
本题考点: 方程的解和解方程;解比例.

考点点评: 本题考查了学生根据等式的性质和比例的基本性质解方程的能力,注意等号对齐.

(2013•渭源县模拟)对于非零的两个实数a、b,规定a×b=[1/b−1a].若1×(x+1)=1,则x的值为-[1/
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1
a].若1×(x+1)=1,则x的值为
-[1/2]
-[1/2]
流浪的心_1 1年前 已收到1个回答 举报

一抹新绿 幼苗

共回答了23个问题采纳率:82.6% 举报

解题思路:首先根据题意可得分式方程:[1/x+1]-1=1,然后解此分式方程即可求得答案.

∵a×b=[1/b−
1
a],1×(x+1)=1,
即[1/x+1]-1=1,
方程的两边同乘(x+1),得:1=2(x+1),
解得x=-[1/2].
检验:把x=-[1/2]代入(x+1)=[1/2]≠0.
∴原方程的解为:x=-[1/2].
故答案为:-[1/2].

点评:
本题考点: 解分式方程.

考点点评: 此题考查了分式方程的应用.此题属于新定义题目,难度不大,注意分式方程需检验.

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解题思路:首先根据题意可得分式方程:[1/x+1]-1=1,然后解此分式方程即可求得答案.

∵a×b=[1/b−
1
a],1×(x+1)=1,
即[1/x+1]-1=1,
方程的两边同乘(x+1),得:1=2(x+1),
解得x=-[1/2].
检验:把x=-[1/2]代入(x+1)=[1/2]≠0.
∴原方程的解为:x=-[1/2].
故答案为:-[1/2].

点评:
本题考点: 解分式方程.

考点点评: 此题考查了分式方程的应用.此题属于新定义题目,难度不大,注意分式方程需检验.

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(2011•渭源县)育红苗圃有一个圆柱形蓄水池,从里面量得底面直径是2米,深1.5米.这个蓄水池占地多少平方米?它能够蓄满5吨水吗?(1立方米水重1吨)
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(2)如果把这个蓄水池注满水,水的体积是求出这个圆柱的容积,先求出水的体积,再求出这些水的重量然后与5吨比较即可.

(1)2÷2=1(米);
3.14×12=3.14(平方米);
(2)3.14×1.5=4.71(立方米);
4.71×1=4.71(吨);
4.71<5;
答:这个蓄水池占地3.14平方米,它不能蓄满5吨水.

点评:
本题考点: 关于圆柱的应用题.

考点点评: 解答此题主要分清所求物体的形状,转化为求有关图形的体积或面积的问题,把实际问题转化为数学问题,再运用数学知识解决.