10x+13-x+9=(13-x)*10+x解方程

有机多面体2022-10-04 11:39:541条回答

10x+13-x+9=(13-x)*10+x解方程
求答案!要过程!谢谢啊.

已提交，审核后显示！提交回复

疯子不要跟着我共回答了17个问题 | 采纳率100%: 10X+13-X+9=(13-X)*10+X
10X+13-X+9=130-10X+X
9X+22=130-9X
18X=130-22
18X=108
X=6; 1年前

10x+13=12x-3说明具体步骤 nongxinks1年前8: zid6881058 共回答了17个问题 | 采纳率88.2%

10x+13=12x-3
10x+13-10x=12x-3-10x
13=2x-3
13+3=2x-3+3
16=2x
16/2=2x/2
x=8

1年前查看全部

计算题:(3x^2+14x+16)/(x+3)-(2x^2-10x+13)/(x-3)-(x^3-9x^2-9x+75) 计算题:(3x^2+14x+16)/(x+3)-(2x^2-10x+13)/(x-3)-(x^3-9x^2-9x+75)/(x^2-9) sky8408281年前2: orcwz 共回答了15个问题 | 采纳率93.3%

(3x^2+14x+16)/(x+3)-(2x^2-10x+13)/(x-3)-(x^3-9x^2-9x+75)/(x^2-9)
=(3x^2+9x+5x+15+1)/(x+3)-(2x^2-6x-4x+12+1)/(x-3)-(x^3-9x-9x^2+81-6)/(x^2-9)
=(3x^2+9x)/(x+3)+(5x+15)/(x+3)+1/(x+3)-[(2x^2-6x)/(x-3)-(4x-12)/(x-3)+1/(x-3)]-[(x^3-9x)/(x^2-9)-(9x^2-81)/(x^2-9)-6/(x^2-9)]
=3x(x+3)/(x+3)+5(x+3)/(x+3)+1/(x+3)-[2x(x-3)/(x-3)-4(x-3)/(x-3)+1/(x-3)]-[x(x^2-9)/(x^2-9)-9(x^2-9)/(x^2-9)-6/(x^2-9)]
=3x+5+1/(x+3)-[2x-4+1/(x-3)]-[x-9-6/(x^2-9)]
=3x+5+1/(x+3)-2x+4-1/(x-3)-x+9+6/(x^2-9)
=3x-2x-x+5+4+9+1/(x+3)-1/(x-3)+6/(x^2-9)
=18+1/(x+3)-1/(x-3)+6/(x^2-9)
=18+(x-3)/(x-3)(x+3)-(x+3)/(x-3)(x+3)+6/(x-3)(x+3)
=18+[(x-3)-(x+3)+6]/(x-3)(x+3)
=18+(x-3-x-3+6)/(x-3)(x+3)
=18

1年前查看全部