1/(x-2)+1/(x+2)+2x/(x平方+4)+4x三次方/(x四次方+16)

一从2022-10-04 11:39:543条回答

1/(x-2)+1/(x+2)+2x/(x平方+4)+4x三次方/(x四次方+16)
如题

已提交,审核后显示!提交回复

共3条回复
priscilla 共回答了24个问题 | 采纳率79.2%
=(x+2+x-2)/(x平方-4)+2x/(x平方+4)+4x三次方/(x四次方+16)
=2x/(x平方-4)+2x/(x平方+4)+4x三次方/(x四次方+16)
=(2x三次方+8x+2x三次方-8x)/(x四次方-16)+4x三次方/(x四次方+16)
=4x三次方/(x四次方-16)+4x三次方/(x四次方+16)
=(4x五次方+16*4x三次方+4x五次方-16*4x三次方)/(x八次方-256)
=8x五次方/(x八次方-256)
1年前
zhangbing8211 共回答了1260个问题 | 采纳率
1/(x-2)+1/(x+2)+2x/(x平方+4)+4x三次方/(x四次方+16)
=2x/(x²-4)+2x/(x²+4)+4x³/(x^4+16)
=4x³/(x^4-16)+4x³/(x^4+16)
=8x^7/(x^8-32)
1年前
以事实说话9 共回答了555个问题 | 采纳率
1/(x-2)+1/(x+2)=[(x+2)+(x-2)]/[(x-2)(x+2)]=2x/(x^2-4)
同理 2x/(x^2-4)+2x/(x^2+4)=2x[(x^2+4)+(x^2-4)]/(x^4-16)=4x^3/(x^4-16)
4x^3/(x^4-16)+4x^3/(x^4+16)=4x^3[(x^4+16)+(x^4-16)]/(x^8-16^2)=8x^7/(x^8-256)
原式=8x^7/(x^8-256)
1年前

相关推荐

4*(x+2)+2x 结果等于8
东林新秀1年前1
寒雨欣 共回答了15个问题 | 采纳率100%
4X+8+2X=8
化简求值:x(x+2y)-(x+2)²+2x 其中x=2,y=½
122310591年前3
etmonkey 共回答了13个问题 | 采纳率92.3%
原式=x²+2xy-x²-4x-4+2x
=2xy-2x-4
=2-4-4
=-6