下各组词语中加点的字,与所给读音不全相同的一组是:( ) A.间jiàn 间断 间或 间歇 挑拨离间 B.冠guān 夺

Tom_文2022-10-04 11:39:541条回答

下各组词语中加点的字,与所给读音不全相同的一组是:( )
A.间jiàn 间断 间或 间歇 挑拨离间
B.冠guān 夺冠 树冠 冠盖 怒发冲冠
C.角jiǎo 角楼 角尺 锐角 转弯抹角
D.蒙méng 承蒙 蒙昧 蒙馆 蒙头转向

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echoB 共回答了13个问题 | 采纳率100%
.选D

“蒙头转向”的“蒙”读mēng。)
1年前

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解题思路:三力合成的范围确定方法:
①三力同向时,合力最大,即F最大=F1+F2+F3
②那么三力合成的范围最小值的确定分三种情况
若F1、F2、F3可够成三角形,即任意两个力加起来大于另一个力且这两个力的差小于第三个力,则最小值为0;
F1、F2、F3无法构成三角形,且其中较小的两个力加起来小于最大的力,则最小值等于最大的力减去其他两个较小力的和;
无法构成三角形,且三个力中最大的力等于另外两个力的代数和,则最小值等于最大的力减去其他两个较小力的和,等于零.

A、8N的力最大,小于另外两个力之和,而大于另外两个力之差,故三个力的合力的最小值为零,故A错误;
B、8N的力最大,小于另外两个力之和,而大于另外两个力之差,故三个力的合力的最小值为零,故B错误;
C、6N的力最大,大于另外两个力之和,故三个力的合力的最小值等于最大的力减去其他两个较小力的和为1N,故C正确;
D、5N的力最大,且等于另外两个力的代数和,故三个力的合力的最小值为零,故D错误;
故选C.

点评:
本题考点: A:力的合成与分解的运用 B:共点力平衡的条件及其应用

考点点评: 本题关键总结出三力合成时求最小值可能出现的三种情况,然后对照规律分析即可.

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