6x平方+7xy+2y平方-8x-5y+2因式分解

endlessspring2022-10-04 11:39:541条回答

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wm418 共回答了18个问题 | 采纳率83.3%: 6x^2+7xy+2y^2-8x-5y+2
=(2x+y)(3x+2y)-(2x+y)-2(3x+2y)+2
=(2x+y-2)(3x+2y-1); 1年前

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6x平方+7xy+2y平方-8x-5y+2因式分解 dongliwu1年前2: tang9797 共回答了18个问题 | 采纳率83.3%

6x^2+7xy+2y^2-8x-5y+2
=(2x+y)(3x+2y)-8x-5y+2
下面我们用待定系数法来解答
(2x+y)(3x+2y)-8x-5y+2=（2x+y+m)(3x+2y+n)
=6x^2+7xy+2y^2+(3m+2n)x+(n+2m)y+mn
mn=2
3m+2n=-8
n+2m=-5
n=-1
m=-2
(2x+y)(3x+2y)-8x-5y+2=（2x+y-2)(3x+2y-1)

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