4m^3 - 16m^2 + 26 ;

山不在矮2022-10-04 11:39:541条回答

4m^3 - 16m^2 + 26 ;
x(a-x)(a-y)-y(x-a)(y-a);
已知x+y=3,xy=2,则多项式 -x^2y - xy^2 的值是多少；

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taoespanya 共回答了22个问题 | 采纳率95.5%: 第一题我再想想...
2.原式=（x-y）（a-x）（a-y）
3.原式=-xy（x+y）
因为x+y=3 xy=2
所以原式=-2×3=-6; 1年前

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1 -4m^3+16m^2-26m
=-4m*(m^2-4m+6.5)
2 5(x-y)^2+10(y-x)^2
=5(x-y)[(x-y)+2(y-x)]
=5(x-y)(y-x)
3 25(a+b)^2-9(a-b)^2
=[5(a+b)+3(a-b)][5(a+b)-3(a-b)]
=[8a+2b][2a+8b]
4 x^5-x^3
=x^3(x+1)(x-1)
5 x^2+2xy+y^2-4
=(x+y+2)(x+y-2)
6 6x-6y-9x^2+18xy-9y^2-1
=6(x-y)-9(x-y)^2-1
=-[3(x-y)-1]^2

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4x^2-y^2=x^2+x+1/4=4a^7-a^5=3a(m-n)+2b(n-m)=4mx^2-8m^2x+4m^3 4x^2-y^2= x^2+x+1/4= 4a^7-a^5= 3a(m-n)+2b(n-m)= 4mx^2-8m^2x+4m^3= x^3y-xy^3= 因式分解, 2x-7-1/7x^2= x^4-16= (x-2y)^2-14(x-2y)+49= (x-y)^3+4(y-x)= (x1+x2)^2-4x1-x2= hua13271年前1: zerojun 共回答了26个问题 | 采纳率96.2%

4x^2-y^2=(2x+y)(2x-y)x^2+x+1/4=(x+1/2)^24a^7-a^5= a^5(2a+1)(2a-1)3a(m-n)+2b(n-m)= (3a-2b)(m-n)4mx^2-8m^2x+4m^3=4m(x-m)^2 x^3y-xy^3= xy(x+y)(x-y)因式分解,2x-7-1/7x^2=-(x^2-14x+49)/7=-(x-7)^2/7 x^4-16= ...

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m^2+4m^3-4-16m 米卡伊凡和阿辽沙1年前2: jcdd_002 共回答了16个问题 | 采纳率93.8%

m^2+4m^3-4-16m
=m^2(1+4m)-4(1+4m)
=(1+4m)(m^2-4)
=(1+4m)(m+2)(m-2)

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