xy^3-cos(x+y)=1,求dy

风景的画2022-10-04 11:39:540条回答

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(1) -(3xy^3)^5-(-3x)^2×(-y)^6×(xy^3)^3= (2)2ab(5ab^2 +3a^2b) (1) -(3xy^3)^5-(-3x)^2×(-y)^6×(xy^3)^3= (2)2ab(5ab^2 +3a^2b)= (3)(-3x^2 y)×(-x^4)×(-y^3)= (4)[3^2×(a^2)^3]^2= glassman851年前1: graceberyl 共回答了13个问题 | 采纳率100%

(1) -(3xy^3)^5-(-3x)^2×(-y)^6×(xy^3)^3= -3^5x^5y^15-9x^2y^6x^3y^9=-243x^5y^15-9x^5y^15=-252x^5y^15
(2)2ab(5ab^2 +3a^2b)= 2abx5ab^2 +2abx3a^2b=2x5a^(1+1)b^(1+2)+2x3a^(1+2)b^(1+1)=10a^2b^3+6a^3b^2
(3)(-3x^2 y)×(-x^4)×(-y^3)=-3*(-1)*(-1)x^(2+4)y^(1+3)=-3x^6y^4
(4)[3^2×(a^2)^3]^2=[6×a^2x3]^2=36a^6x2=36a^12

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(-1/2xy^2)-1/6x(xy^3)^2=? hwsun20001年前1: yxuzhoue 共回答了16个问题 | 采纳率81.3%

(-1/2xy^2)-1/6x(xy^3)^2=-1/2xy^2-1/6x^2y^6=-1/2xy^2(1+1/3xy^4)

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X^3Y-2X^2Y^2+XY^3 X^3Y-2X^2Y^2+XY^3 分解因式 kepy1年前1: hao596 共回答了18个问题 | 采纳率77.8%

答：
X^3Y-2X^2Y^2+XY^3
=x³y-2x²y²+xy³
=xy(x²-2xy+y²)
=xy(x-y)²

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