an=(1/2+...+1/2^(2n-1))

bornformovie72022-10-04 11:39:541条回答

an=(1/2+...+1/2^(2n-1))
Sn=2/3 • (1-1(1/2)^2n)

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西山晴雪_1982 共回答了11个问题 | 采纳率81.8%
an=(1/2+...+1/2^(2n-1)) 还是 an= 1/2^(2n-1)
这里的 Sn 指的是什么,数列{an}的前n项和吗?
1年前

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