(a^3+1/5a^2`b+3)-1/2(a^2`b-6)

canyue2202022-10-04 11:39:541条回答

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(a^3+1/5a^2`b+3)-1/2(a^2`b-6)
=a^3+1/5a^2`b+3-1/2a^2`b+3
=a^3+3/10a^2b+6
1年前

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