x+2y+x-2y分之4y平方-x-4y平方分之4x平方y

负手立大荒2022-10-04 11:39:541条回答

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若鹏糖醋鲤鱼 共回答了15个问题 | 采纳率86.7%
x+2y+4y^2/(x-2y)-4x^2y/(x-4y^2)
=x+2y+4y^2/(x-2y)-4x^2y/[(x+2y)(x-2y)] 通分,分母为[(x+2y)(x-2y)]
=(x+2y)(x+2y)(x-2y)/[(x+2y)(x-2y)]+[4y^2(x+2y)]/[(x+2y)(x-2y)]-4x^2y/[(x+2y)(x-2y)]
=[(x+2y)^2(x-2y)+4y^2(x+2y)-4x^2y]/[(x+2y)(x-2y)] 一、二项合并
={(x+2y)[(x+2y)(x-2y)+4y^2]-4x^2y}/[(x+2y)(x-2y)]
=[(x+2y)x^2-4x^2y]/[(x+2y)(x-2y)]
=(x^3-2yx^2)/[(x+2y)(x-2y)]
=x^2(x-2y)/[(x+2y)(x-2y)]
=x^2/(x+2y)
1年前

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TY_Cruz1年前1
cqjboy2007 共回答了14个问题 | 采纳率92.9%
=[(x+2y)(x-2y)+4y²]/(x-2y)-4x²y/ (x+2y)(x-2y)
=x²/(x-2y)-4x²y/(x+2y)(x-2y)
=(x³+2x²y-4x²y)/(x+2y)(x-2y)
=x²/(x+2y)

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