x+xy+xyz+xyzq=5432,求x=?y=?z=?q=?

x+xy+xyz+xyzq=5432
x+xy+xyz+xyzq=x(1+y+yz+yzq)=5432 x=2
1+y+yz+yzq=2716 y+yz+yzq=y(1+z+zq)=2715 y=5
1+z+zq=543 z+zq=z(1+q)=542 z=2 q=270
x+xy+xyz+xyzq=2+2x5+2x5x2+2x5x2x270=5432

x=4
y=8
z=9
q=1