(x^2-zxy+y^2)+(-zx+zy)+1 (x^2-zxy+y^2)+(-zx+zy)-1 分解因式,

syw9902022-10-04 11:39:541条回答

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korla7a 共回答了23个问题 | 采纳率95.7%: (x^2-2xy+y^2)+(-2x+2y)+1
=(x-y)^2-2(x-y)+1
=[(x-y)-1]^2=(x-y-1)^2
(x^2-2xy+y^2)+(-2x+2y)-1
=(x-y)^2-2(x-y)-1
=[(x-y)^2-2(x-y)+1]-2
=(x-y-1)^2-(√2)^2
=(x-y-1+√2)(x-y-1-√2); 1年前

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