A:-30 B:10 C:18 A:6/s B,C:3/s ①当t=?AB=AC?②t=?AB=1/3AC?③t≠5 O

DDD7382022-10-04 11:39:542条回答

A:-30 B:10 C:18 A:6/s B,C:3/s ①当t=?AB=AC?②t=?AB=1/3AC?③t≠5 OA中点P OB:M OC:N 求PM-PN=2 t=?
/s表示每秒移动!s表示秒 正方向!都在数轴上 A表示 -30 B表示 10 C 表示 18 A六个单位每秒 B和C都是每秒三个单位 设运动t(秒).
1.t为何值时 AB=AC?
2.t为何值时 AB=1/3AC?
3.t≠5时,设OA中点为P OB中点为M OC中点为N 求PM-PN=2时t的值.

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cj6g4fmp6 共回答了21个问题 | 采纳率85.7%
1,44/3秒;2,12秒或14秒;3,46/3秒
A:-30+6t
B:10+3t
C:18+3t
1,AB=|(10+3t)-(-30+6t)|=|40-3t|
AC=|(18+3t)-(-30+6t)|=|48-3t|
AB=AC,|40-3t|=|48-3t|,平方并整理可解得t=44/3秒
2,|40-3t|=1/3|48-3t|,解得t=12秒 或t=14秒
3,P:-15+3t M:5+1.5t N:9+1.5t
PM=|(5+1.5t)-(-15+3t)|=|20-1.5t|
PN=|(9+1.5t)-(-15+3t)|=|24-1.5t|
|20-1.5t| - |24-1.5t|=2
分类讨论去掉绝对值,解得t=46/3秒
1年前
wuxinyu2004 共回答了1个问题 | 采纳率
1,44/3秒;2,12秒或14秒;3,46/3秒
A:-30+6t
B:10+3t
C:18+3t
1年前

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