∫(sinx^1/2)/(x^1/2)dx请问这个怎样解决啊

这个吧
∫sin√x/√x dx
令t=√x,则x=t²,dx=2t dt,代入原式得
=∫sint/t*2t dt
=2∫sint dt
=-2cost
=-2cos√x+C

=∫(sinx^1/2)/(x^1/2)*2(x^1/2)d(x^1/2)
=2∫sinx^1/2d(x^1/2)
=-2cosx^1/2+C