如表是建厂地点与成本分析表．据表回答17～18题．

110,000-volt power supply equipment
 
This set of equipment included the disconnectors, surge arresters, voltage extraction device that No.9 water plant use in 1988 when it first started. All parts are mounted on an overhead fram. No.9 water plant is the only factory that equipt with 110,000 volts power supply. The set of equipment retired in 2013 after power distribution equipment modification.
Less oil circuit breakers
 
This less oil circuit breakers was put into use at No.9. water plant in 1988. Composed with contact, conductive systems and extinguishing systems. The set of equipment retired in 2013 after power distribution equipment modification.

s h i t

小题1:D
小题2:B

The 110000 volt power supply equipment
This set of equipment is isolating switch,lightning arrester,voltage extracting device using ninth plant in 1988 and build factories,are installed in the door type elevated,at present only ninth water using high voltage power supply to 110000 volts.This set of equipment of substation equipment renovation in 2013 after retirement.
Less oil circuit breaker
The less oil circuit breaker in 1988 in the ninth plant put into use,composed of a contact,the conductive system and arc extinguishing system.This set of equipment of substation equipment renovation in 2013 after retirement.

就是把三项成本相加得到费用最低的经济效益最好,三项成本相加得到费用最高的经济效益最差.
甲是17,乙是25,丙是22,丁是18.
答案：A.甲地

我告诉你方法,请你自己算：
1、因为圆的直径都是等长的,有无数条直径,所以,假想一下就知道最大圆的直径不可能超过长方形的长即为2分米,则半径为1分米,根据圆面积公式即可求出茶杯垫面积.
2、因为缠草绳不可能每一圈都首尾向接,所以60圈实际为61层,即高为61个草绳直径；而需草绳的长由于绕60圈,即有60个树的周长,树直径10厘米,即半径为5厘米,用公式求树的周长再乘于60即可.

小题1:D
小题2:B


小题1:从经济效益角度看，就是布局在成本最低的位置。那么甲处成本：3+5+12=20；乙处成本：4+5+16=25；丙处成本是：6+5+11=22；丁处成本是:6+5+7=18.所以布局在丁处成本最低。选择D项。
小题2:根据图中信息可知，乙处主要是工资水平最高，所以发展高技术型工业。选择B项。

a

D

⑴：汽船、火车
⑵：棉纺织行业    棉纺织行业较发达，机器取代了手工生产
⑶：电力机、内燃机
⑷：汽车、飞机 

解题思路：影响工业区位的成本因素较多，各项成本因素对不同行业的区位吸引力不同．

阅读表格资料可知，乙地生产一件产品的成本是：4+5+16=25（元），高于其他三地，所以该地兴办企业适宜发展时装公司、软件开发公司和移动通信器材研发公司．根据题意．
故选：C．

点评：
本题考点： 地理常识．

考点点评： 该题主要考查影响工业区位的因素，理解解答即可．

Why we are against the construction of the chemical factory
As a school we have a duty to protect the health and safety of our children. We do not dispute the fact that the chemical factory will bring in new revenues to our city. However these revenues come at a tremendous cost. It is a well-known fact that chemical factories produce great quantities of polluted industrial waste water and toxic gases. This will result in the contamination of the water we drink, the air we breathe, and the ground that we live and play on. Furthermore, it will displace a large part of the school children's play areas. In short, the costs will far exceed any financial benefits that the city hopes to get from the factory.
满意请及时采纳,谢

解题思路：此题是关于苔藓植物与人类的关系的选择题，据此答题．

苔藓植物无根，有茎、叶的分化，但体内无输导组织，叶只有一层细胞构成，二氧化硫等有毒气体容易从背腹两面侵入而威胁苔藓植物的生活，因此我们常把苔藓植物作为检测空气污染程度的指示植物，火力发电厂由于燃煤产生二氧化硫，会影响苔藓植物的生存，因此在污染严重的火力发电厂附近，苔藓植物一般很少见．可见B符合题意．
故选：B

点评：
本题考点： 苔鲜的主要特征及其与人类生活的关系．

考点点评： 关键是掌握苔藓植物的意义，结合题意，即可做出正确的选择．

按照你给出的数据是可以计算排污费的,以下计算方法是基于国家规定征收标准进行计算的,如果你们当地物价和环保部门有制定地方征收价格的话可能具体金额会不对,但计算公式是通用的.
废水部分：
通过废水总量乘以排放浓度然后单位换算以后可以得出：COD月排放量16000kg,SS月排放量4450kg,石油类月排放量1050kg,通过排放量除以当量值后可以得出：COD月污染当量数16000,SS为1112.5,石油类为10500,PH值为50000,根据规定废水征收污染当量数最高的三项（COD、石油类、PH）乘以单价0.7元/当量数,得出基本污水排污费为53550元,根据规定超标排放的要加1倍征收排污费（PH值除外）得出加倍征收金额为18550元.合计得出月废水排污费为72100元/月.
废气：
根据标杆烟气量乘以月开炉时间得出月废气排放量为15000000立方米.使用月废气排放量乘以排放浓度并单位换算后得出：二氧化硫月排放量12000kg,烟尘月排放量4500kg,氮氧化物月排放量6000kg,通过排放量除以当量之后可以得出：二氧化硫月污染当量数为12632,烟尘为2064,氮氧化物为6316,3项污染物当量数相加后乘以单价0.6元/当量数得出月废气排污费为12607元.
根据以上计算方法,废水与废气相加,该厂月应缴排污费总额是84707元.
参考《排污费征收标准管理办法》