若(3x^2y-2xy^2)/M=-3x+2,则单项式M等于

过客GONE2022-10-04 11:39:541条回答

已提交,审核后显示!提交回复

共1条回复
pipi_0319 共回答了15个问题 | 采纳率86.7%
(3x^2y-2xy^2)/M=-3x+2
M=(3x^2y-2xy^2)/(-3x+2)
=xy(3x-2y)/(-3x+2)
题目是否有问题,最后少掉一个y;如果:题目变为:(3x^2y-2xy^2)/M=-3x+2y
则:M=xy(3x-2y)/(-3x+2y)
M=-xy
1年前

相关推荐

已知xy=2,x-y=3,求(x+y)(x-y)-y^2+(x-y)^2-(6x^2y-2xy^2)/2y的值.
89757zx1年前2
lenovo3721 共回答了18个问题 | 采纳率77.8%
(x+y)(x-y)-y^2+(x-y)^2-(6x^2y-2xy^2)÷2y
=(x+y)(x-y)-y^2+(x-y)^2-2y(3x^2-xy)÷2y
=(x+y)(x-y)-y^2+(x-y)^2-(3x^2-xy)
=(x+y)(x-y)+(x-y)^2-y^2-(3x^2-xy)
=[(x+y)+(x-y)](x-y)-y^2-(3x^2-xy)
=2x(x-y)-y^2-(3x^2-xy)
=2x^2-2xy-y^2-3x^2+xy
=-x^2-xy-y^2
=-(x^2+y^2+xy)
=-(x^2-2xy+y^2+3xy)
=-[(x-y)^2+3xy]
=-[3^2+3*(-2)]
=-(9-6)
=-3
已知xy=2,x-y=3,求(x+y)(x-y)-y^2-(6x^2y-2xy^2)/2y的值.
lulusix1年前3
大将军卫青 共回答了9个问题 | 采纳率88.9%
(x+y)(x-y)-y^2-(6x^2y-2xy^2)/2y
=x^2-y^2-y^2-3x^2+xy
=-2(x^2+Y^2)+xy
=-2(x^2+Y^2-2xy)-4xy+xy
=-2(x-y)^2-3xy
=-2*3^2-3*2
=-24
(x+y)(x-y)+(x-y)^2-(6x^2y-2xy^2)/2Y,其中x=-2,y=1/3
jxt_go41年前2
shjn41 共回答了25个问题 | 采纳率96%
最后的Y是y吗?
如果是,原式化简后为-x^2,结果为-4