希望高手相助,小女子感激不尽^-^竞赛化学题目.

Polaris_1142022-10-04 11:39:541条回答

希望高手相助,小女子感激不尽^-^竞赛化学题目.
某学生为测定CuS的溶度积常数,设计如下原电池;正极为铜片浸在0.1摩尔每升的二价铜离子溶液中,在通入硫化氢气体使之达到饱和;负极为标准锌电极.测的电动势为0.760伏特.求CuS的溶度积常数.(фCu2+/Cu= 0.34 фZn2+/Zn=0.763 H2S K1=1.3/10000000 (7个0) K2=7.1/1000000000000000 (15个0) )

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如此这样 共回答了15个问题 | 采纳率93.3%
通入硫化氢气体使之达到饱和
即当Cu2+完全反应生成0.2mol/L H+ 后,溶液中硫化氢气体还饱和,则溶液中硫化氢浓度为0.1 mol/L (这是分析化学常识)

计算溶液剩余的Cu2+可由下式直接求
Cu2+ + H2S= CuS ↓ + 2H+
X 0.1 mol/L 0.2 mol/L
(0.2)^2 /[0.1*X]=(Ka1*Ka2 )/Ksp-----(1)

正极:фCuS/Cu= ф0Cu2+/Cu+ 0.0591/2*lg[Cu2+] -----(2)
负极: фZn2+/Zn=-0.763 V
则:0.760 V=фCuS/Cu-(-0.763V)
фCuS/Cu=-0.003V 然后代入(2)式
解得:[Cu2+]=2.45*10^-12mol/L
再代入(1)式得
Ksp=5.7*10^-33
(没有按有效数字规则计算)

--------------------
当然也可由电池计算[Cu2+]
正极:фCuS/Cu= ф0Cu2+/Cu+ 0.0591/2*lg[Cu2+] -----(2)
负极: фZn2+/Zn=0.763
则:0.760 V=фCuS/Cu-(-0.763V)
фCuS/Cu=-0.003V 然后代入(2)式
解得:[Cu2+]=2.45*10^-12mol/L

然后再分布系数计算[S2-]
[S2-]=c(H2S)* Ka1*Ka2 /{[H+]^2 +[H+]*Ka1+ Ka1*Ka2 }
=0.1mol/L * [ (1.3*10^-7)*(7.1*10^-15) ] / { (0.2)^2 + 0.2*(1.3*10^-7) + (1.3*10^-7)*(7.1*10^-15)}=2.31*10^-20mol/L
Ksp(CuS)=[Cu2+]*[S2-]=(2.45*10^-12)*(2.31*10^-20)=5.7*10^-33

希望对你有帮助
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第二段
第一行The goal is to offer several courses sportives and recreationals. 改为The goal is to offer several courses sportive and recreational.
第二行The course consist of competitive barriers which is built by obstacles worthy of Olympic disciplines: the hedges, the horizontal bar, the swimming ... 改为The course consists of competitive barriers which is built by obstacles with Olympic disciplines: the hedges, the horizontal bar, the swimming ...
最后So our customers are particularly young people, what are the benefits of our business. The course consists normally 5 to 7 Barriers. 改为So our customers are particularly young people, who provide the benefits of our business. The course consists of normally 5 to 7 Barriers.
希望能帮到你!
圆弧求弧长!弦长14.1m,5m,求弧长..希望高手给出具体的过程,运算过程也写清楚!不要简洁的答案.
怡心宝宝1年前2
jnoe2005 共回答了18个问题 | 采纳率94.4%
弦长L=14.1m,弦高H=1.5m,求弧长C?
弧半径为R,弧所对的圆心角为A.
R^2=(R-H)^2+(L/2)^2
R^2=R^2-2*R*H+H^2+L^2/4
2*R*H=H^2+L^2/4
R=H/2+L^2/(8*H)
=1.5/2+14.1^2/(8*1.5)
=17.3175m
A=2*ARC SIN((L/2)/R)
=2*ARC SIN((14.1/2)/17.3175)
=48.05度
=48.05*PI/180
=0.83856弧度
C=A*R
=0.83856*17.3175
=14.522m
希望高手大哥们前来帮忙 在这先谢谢了
希望高手大哥们前来帮忙 在这先谢谢了
用英文单词写作文 要求 1.一封爱的告白书 2.男方名字牛;女方名字娇娇 3.男方给女方的信 4.80以上单词 5.工整 经典
czjzjh1年前1
吃狼的兔妹妹 共回答了15个问题 | 采纳率80%
Dear Jiaojiao:
Do you believe in love at first sight?Before I was not believe it,but when I met you,I just know love at first sight originally is so beautiful.
Love a person is very bitter.Why I can't stop pay!
You PinTing gracefuls and the charm of the,delicate and charming pretty appearance,dignified and good manners,elegant and generous manner of speaking,start impressing me.
I think in five years later,I must still like now love you.
Everyday I see you,and power is talk with you.
No one can understand now of I,like every poet's repeated roads in general.
Really want to be with you,even his own life,and the fire of the upcoming extinguished regretless without shake.
Because of my volunteer is with you together to fly to the distant horizon
I really cannot bear,although I face hangs senseless smile,but my heart was very sad,really,many of the night I asked myself as I do wrong?
If today's every day,thoughts and love thought has dominated my thoughts,I want to control,but I can't,drizzle of the heart-to-heart lasting acquaintanceship teahouse but my love will never change!
Yous
Cows
娇娇:
你相信一见钟情吗?以前我总是不相信,可是当我遇见了你,我才知道一见钟情原来是那么地美好.
爱一个人是很苦的事.为什么我却不能停止付出!
你娉婷婉约的风姿,娇艳俏丽的容貌,端庄得体的举止,优雅大方的谈吐,一开始就令我刮目相看.
我想在五十年之后,我一定还是像现在一样爱你.
每天我的动力就是见到你,并和你说说话.
无人能理解现在的我,就象每个诗人的反复咏叹一般.
好想和你在一起,即使自己的生命之火即将熄灭,也无悔无撼.
因为我的志愿是和你一同飞向遥远的天边
我真的是承受不了,虽然我脸上挂着无谓的笑容,但是我内心十分难过,真的,多日的黑夜我问我自己是我做错了什么?
如今天的每一天,思念与爱念已占据了我的思想,我想控制,可是我没办法,细雨中的相识茶座中的谈心海枯石烂但我的爱永不变!
Yours
Cows