x²-5x+6≤0

5x+54x²-24-54x²-144x+54=2
-119x+30=2
119x=28
x=4/17

第一题:
分解因式:
(x-2)(2x+1)>0
解得:x2
第二题:
分解因式:
(x-1)(x+6)

(2x-5)/(x^2-5x+6)-1/(x-3)
=(2x-5-(x-2))/(x-2)(x-3)
=(x-3)/(x-2)(x-3)
=1/(x-2);
很高兴为您解答,skyhunter002为您答疑解惑
如果本题有什么不明白可以追问,

原式=(x-2)(x-3)/(x-2)(x-4)=(x-3)/(x-4)
所以极限=(2-3)/(2-4)=1/2

62
.

右边移到左边
(2x^2 -x + 7) / ( x^2 -5x + 6) >=0
第一个括弧内总大于零
只要第二个括弧大于零就好
得到 x3

x²-5x+6≤0
(x-2)(x-3)≤0
2≤x≤3

是解不等式：（x^2-1)/(x^2-5x+6)

5/(x-3)(x+2) -6/(x+2)(x-2)=4/(x-2)(x-3)
两边乘以(x-3)(x+2)(x-2)得
5(x-2)-6(x-3)=4(x+2)
5x-10-6x+18=4x+8
-5x=20
x=-4
检验：x=-4是方程的解

原式
=（x+3）分之1-（x-2）（x-3）分之（x-2）
=（x+3）分之1-（x-3）分之1
=[（x+3）（x-3）]分之[（x-3）-（x+3）]
=（x²-9）分之（-6）
=-（x²-9）分之6

(x^2+2x-3)/(x^2-9)*(x^2-5x+6)/(3x^2-x-2)
什么题目?简化?
(x^2+2x-3)/(x^2-9)*(x^2-5x+6)/(3x^2-x-2)
=（x+3）（x-1）/[（x+3）（x-3）]*（x-2）（x-3）/[（3x+2）（x-1）]
=（x-2）/（3x+2）

(x-1)/(x^2-5x+6)+(x-2)/(x^2-4x+3)+(x-3)/(x^2-3x+2) = (x-1)/{(x-2)(x-3)} + (x-2)/{x-1)(x-3)} + (x-3)/{(x-1)(x-2)}= { (x-1)^2 + (x-2)^2 + (x-3)^2 } / { (x-1)(x-2)(x-3) }= (x^2-2x+1+x^2-4x+4+x^2-6x+9) / ...

1.将3个分数化成6个,当然其中要有一定的技巧分配.
看分母是(x-1)(x-2)(x-3)的组合,所以想到将分子也配成这样的来化简：[(x^3-4x)-(x^2-1)]/[(x-2)(x-1)] - [(x^3-4x^2+4x)+(2x^2-13x+21)]/[(x-2)(x-3)] + [(x^2-7x+12)+(4x-4)]/[x-3)(x-1)]
= [x(x+2)(x-2)-(x+1)(x-1)]/[(x-2)(x-1)] - [x(x-2)^2+(2x-7)(x-3)]/[(x-2)(x-3)] + [(x-3)(x-4)+4(x-1)]/[x-3)(x-1)]
想式子化简成6个只有1个分母的式子：[x(x+2)]/(x-1) - (x+1)/(x-2) -[x(x-2)]/(x-3) - (2x-7)/(x-2) + (x-4)/(x-1) + 4/(x-3)
再将分母相同的组合在一起：[x(x+2)+(x-4)]/(x-1) - [(x+1)+(2x-7)]/(x-2) -[x(x-2)-4]/(x-3)
=(x^2+3x-4)/(x-1) - (3x-6)/(x-2) - (x^2-2x-4)/(x-3)
=[(x-1)(x+4)]/(x-1) - [3(x-2)]/(x-2) - [(x^2-2x-3)-1]/(x-3)
=(x+4)- 3 - [(x+1)(x-3)-1]/(x-3)
=x+1 - {[(x+1)(x-3)]/(x-3)-1/(x-3)}
=x+1-{(x+1)-1/(x-3)
=1/(x-3)
2. 这个题觉得你写的可能会出现歧义,我是以以下式子
{(x^2)/(x-y)}*{y/(x+y)}-{(y*x^4)/(x^4-y^4)}÷{(x^2)/(x^2+y^2)^2}
=(y*x^2)/(x^2-y^2) - {(y*x^4)/[(x^2+y^2)(x^2-y^2)]} × {[(x^2+y^2)^2]/(x^4)}
对后面式子进行化简,主要是约分(如果这样不好看 请自己将上式用分数写下来)：
=(y*x^2)/(x^2-y^2) - {y(x^2+y^2)}/(x^2-y^2)
=(y*x^2)/(x^2-y^2) - {(y*x^2)/(x^2-y^2)+(y^3)/(x^2-y^2)}
= -(y^3)/(x^2-y^2)

.x>=-4且x不等-5/3
x<-5或x>-1且不等2
x>=（根17-3）/2或x<=-(根17+3）/2
题目不对
x<=-5或-1<=x<=2或x>=3
当0=2 x>1或x<2/m 当m<=0 x>1 或 (当02/m 当m<=0 x<2/m 当m>2 2/m

1年前

5

(2)A=2
(1)大于等于根号3 ,x=2时最小

6*6+2*(-5)+(-5)*2+(-3)*4=4

x²-5x+6；=(x-2)(x-3)
x²-5x-6；=(x-6)(x+1)
x²+5x-6；=(x+6)(x-1)
x²+3x-18；=(x+6)(x-3)
x²-2x-15；=(x-5)(x+3)
a²+7a+10,=(a+2)(a+5)
a²b²-7ab+10；=(ab-2)(ab-5)
x²+4x+3；=(x+3)(x+1)
y²-7y+12；=(y-3)(y-4)
m²+7m-18；=(m+9)(m-2)
p²-5p-36；=(p-9)(p+4_
a²+3ab+2b²；=(a+2b)(a+b)
x²-5xy-6y²；=(x-6y)(x+y)
2p²-3p+1；=(2p-1)(p-1)
m²+2mn-3n²；=(m+3n)(m-n)
a²-9ab+20b²；=(a-4b)(a-5b)
3m²+4m+1；=(3m+1)(m+1)
x³y-3x²y²+2xy³；=xy(x²-3xy+2y²)=xy(x-2y)(x-y)
-x的4次方+3x³+28x²；=-x²(x²-3x-28)=-x²(x-7)(x+4)
（x²-3x）²-（3x+7）²；=(x²-3x+3x+7)(x²-3x-3x-7)=(x²+7)(x²-6x-7)=(x²+7)(x-7)(x+1)
（x+y）²+8（x+y）-48=(x+y+12)(x+y-4)

√（5x+6)=-x
5x+6=x^2
x^2-5x-6=0
(x-6)(x+1)=0
x=6,或x=-1
经检验,x=6舍去,
所以x=-1

（-ab+2)(5ab-3)-ab(1-ab)
=-5a^2b^2+13ab-6-ab+a^2b^2
=-4a^2b^2+12ab-6
(-2x)·(x^2-5x+6)-4x(2x^2-3x+1)
=-2x^3+10x^2-12x-8x^3+12x^2-4x
=-10x^3+22x^2-16x

|x²-5x+6|-|x²+3x-10|
=|(x-2)(x-3)|-|(x+5)(x-2)|
(a) ∵当x>4时,x-2>2>0、x-3>1>0、x+5>9>0
∴(x-2)(x-3)>0、(x+5)(x-2)>0
∴|x²-5x+6|-|x²+3x-10|
=|(x-2)(x-3)|-|(x+5)(x-2)|
=(x-2)(x-3)-(x+5)(x-2)
=x²-5x+6-x²-3x+10
=-8x+16
(b) ∵当2

（-2x)*(x2-5x+6)-4x(2x2-3x+1)
=-2x³+10x²-12x-8x³+12x-4x
=-10x³+22x²-16x
如果本题有什么不明白可以追问,

(x+a-1)/(a-x)>0
(x+a-1)(x-a)

不知道你的要求是不是化简,而且很多地方表达的有歧义性.我按化简这个方向和自己猜的提意做,你看对否?
1) [1/(x²-3x+2)] + [1/(x²-5x+6)] + [1/(x²-4x+3)]
原式=[1/(x-1)(x-2)]+[1/(x-2)(x-3)]+[1/(x-1)(x-3)]
=[(x-3)/(x-1)(x-2)(x-3)]+[(x-1)/(x-1)(x-2)(x-3)]+[(x-2)/(x-1)(x-2)(x-3)]
=[x-3+x-2+x-1]/[(x-1)(x-2)(x-3)]
=[3x-6]/[(x-1)(x-2)(x-3)]
=3/[(x-1)(x-3)]
2) [(x-1)/(x²+3x+2)] + [6/(2+x-x²)] -[(10-x)/(4-x²)]
原式=[(x-1)/(x+1)(x+2)]+[6/(x+1)(2-x)]-[(10-x)/(2-x)(2+x)]
=[(x-1)(2-x)/(x+1)(x+2)(2-x)]+[6(x+2)/(x+1)(x+2)(2-X)]-[(10-x)(1+x)/(1+x)(2+x)(2-x)]
=0/ [(1+x)(2+x)(2-x)]
=0
3) [（x+1)-1/(1-x）]÷[（x)-x²/(x-1）]
原式= [(x+1)(1-x)/(1-x)]-[1/(1-x)]÷[x(x-1)/(x-1)]-[x²/(x-1)]
=[(-x²)/(1-x)]÷[(-x)/(x-1)]
=[(-x²)/(1-x)]×[(1-x)/x]
=-x
4) [（x²-4)/(x²-x-6) +(x+2)/(x-3)]÷[（x+1）/（x-3）]
原式=[(x-2)(x+2)/(x-3)(x+2)+(x+2)/(x-3)]÷[(x+1)/(x-3)]
=[(x-2)/(x-3)+(x+2)/(x-3)]×[(x-3)/(x+1)]
=[2x/(x-3)]×[(x-3)/(x+1)]
=2x/(x+1)
5) x/(x-y) ·y²/(x+y) - x^4y/(x^4-y^4) ÷ x²/(x²+y²)
原式=xy²/(x²-y²)-x^4y/(x²+y²)(x²-y²)×(x²+y²)/x²
=xy²/(x²-y²)-x²y/(x²-y²)
=(xy²-x²y)/(x²-y²)
=xy(y-x)/(x+y)(x-y)
=-xy/(x+y)
PS 麻烦写的规范点实在是看的累

分母有理化
x=√5-2
x+2=√5
平方
x²+4x+4=5
x²+4x=1
所以原式=x²+4x-9x+6
=1-9x+6
=7-9x
=7-9(√5-2)
=25-9√5

1.x^2-9=0,则(x^2-5x+6)/(x-3)的值?
x^2=9
x=±3
(x^2-5x+6)/(x-3)
=(x-2)(x-3)/(x-3)
因为x-3是分母 所以x-3≠0,x≠3.所以x1=3（舍）.
所以x=-3.
把x=-3代入原式.
-5×(-6)/(-6)
=-5
2.已知2x-y=0,求分式 1+(2y^2)/(x^2-y^2) 除以 1+(2y)/(x+y)的值?
(请把后面的分式运算过程写清)
1+(2y^2)/(x^2-y^2) 除以 1+(2y)/(x+y)
=1+(2y^2)/(x^2-y^2) 乘以 (x+y)/1+2y
=1+2y^2/(x+y)(x-y)乘以(x+y)/1+2y
=1+2y^2/x-y乘以1/1+2y
=1+2y^2/(x-y)(1+2y)
2x-y=0 y=2x
把y=2x代入原式.
1+8x^2/-x(1+4x)
=1+8x^2/4x^2-1