因式分解x^9+x^6+x^2-3

carara2022-10-04 11:39:543条回答

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xiaoye1234 共回答了14个问题 | 采纳率92.9%: x^9+x^6+x^2-3
=（x^9-1）+（x^6-1）+（x^2-1）
=（x^3-1)(x^6+x^3+1)+(x^2-1)(x^4+x^2+1)+(x^2-1)
=(x-1)(x^2+x+1)( x^6+x^3+1)+(x^2-1)(x^4+x^2+2)
=(x-1)(x^2+x+1)( x^6+x^3+1)+(x+1)(x-1)(x^4+x^2+2)
=(x-1)[(x^2+x+1)( x^6+x^3+1)+(x+1)(x^4+x^2+2)]
=（x-1）（x^8+x^7+x^6+2x^5+2x^4+2x^3+2x^2+3x+3); 1年前

wangzheng231 共回答了6个问题 | 采纳率: x^9+x^6+x^2-3=(x^9-1)+(x^6-1)+(x^2-1)
=(x^3-1)( x^6+x^3+1)+(x^3-1)( x^3+1)+ (x+1)(x-1)
=(x-1)(x^2+x+1)( x^6+x^3+1)+(x-1)(x^2+x+1) ( x^3+1)+ (x+1)(x...; 1年前