因式分解8x的n+2次方-12x的n次方+4x的n-2次方（n为大于2的整数）

8x^(n+2)-12x^n+4x^(n-2)
=4x^(n-2)(2x^4-3x^2+1)
=4x^(n-2)(x^2-1)(2x^2-1)
=4x^(n-2)(x+1)(x-1)(√2x+1)(√2x-1)
^表示指数.

8x^(n+2)-12x^n+4x^(n-2)
=4x^(n-2)[2x^4-3x^2+1]
=4x^(n-2)[(2x^2-1)(x^2-1)]
=4x^(n-2) (√2x+1)(√2x-1)(x+1)(x-1)