Math question 0001! (^__^) O(∩_∩)0 \(^o^)/~

小猫mimi2022-10-04 11:39:541条回答

Math question 0001! (*^__^*) O(∩_∩)0 (^o^)/~
请写出具体过程：
规定一种运算：a*b=ab+a+b,则a*(-b)+a*b计算结果为（）
A.0 B.2a C.2b D.2ab

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A math question,please. A math question,please. I have to result this question by my exam,could any one help me? question: A car park measures 15 metres by 18 metres.A car occupies 6 square metres but two-fifths of the park must be left free for turing.What is the maximum cpacity of the car park? A.18 B.3 C.36 D.9 E 27 I see the answer for E.i don't understand a lot. thanks for everybody who could get us a reasonable answer. Thank you! 如果复杂就用CHINESE吧,我的英文understanding比较limited 天使消失的街角1年前3: ll四野共回答了24个问题 | 采纳率100%

For each car,the real space is not 6,but 6 /(3/5) = 10
Then total number of cars in this parking lot:
15*18/10 = 3x9 = 27

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a math question(a-b)^5÷(b-a)^2= (最终结果）(p-q)^5÷(q-p)^2·（p-q)^ a math question (a-b)^5÷(b-a)^2= (最终结果） (p-q)^5÷(q-p)^2·（p-q)^3 （计算要有过程） （-1.1×10^4)（2.3×10^5）÷（-5.06×10^3) （计算要有过程） ronghuii1年前3: aileen5791 共回答了20个问题 | 采纳率90%

(a-b)^5÷(b-a)^2=(a-b)^5÷(a-b)^2
=(a-b)^3
(p-q)^5÷(q-p)^2·（p-q)^3
=(p-q)^5÷(p-q)^2·（p-q)^3
=(p-q)^3·（p-q)^3
=(p-q)^6
（-1.1×10^4)（2.3×10^5）÷（-5.06×10^3)
=（-1.1×2.3×10^9）÷（-5.06×10^3)
=（-2.53×10^9）÷（-5.06×10^3)
=(2.53×10^9）÷（5.06×10^3)
=(2.53÷5.06)×10^6
=5x10^5

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Math question,please solve:Q54 L D 4 K Y N U8P 8XG 9TU QNG U Math question,please solve:Q54 L D 4 K Y N U8P 8XG 9TU QNG U 6 1 YB4 9T7 O clsc4cls1年前1: yangxh9928 共回答了18个问题 | 采纳率94.4%

Q54 L D 4 K Y N U8P 8XG 9TU QNG U 6 1 YB4 9T7 O

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math question (english) math question (english) find the equation of the line such that the x-axis bisects the angle between it and the line 2x-3y-6=0 find the equations of the two lines through the origin which make angles of 45° with the line 2x+3y-4＝0 战斗的公牛1年前1: 王芊的kk 共回答了23个问题 | 采纳率91.3%

1.y=2x/3-2,斜率是2/3,于x轴交于(3,0)
所以直线过(3,0),斜率是-2/3
即y=-2x/3+2
2.y=-2x/3+4/3,斜率是-2/3
设新斜率是x,1=(x-2/3)/(1+2x/3) or -1=(x-2/3)/(1+2x/3)
1+2x/3=x-2/3 or -1-2x/3=x-2/3
x=5 or -1/5
所以直线为y=5x和y=-x/5

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Math question 0001! (*^__^*) O(∩_∩)0 \(^o^)/~