求设公式:1转换成2,如下图.

sin(xy)-1/y-x=1
[dsin(xy)/d(xy)*d(xy)/dx]-(-y'/y²)-1=0
cos(xy)*(y+xy')+y'/y²-1=0
ycos(xy)+xy'cos(xy)+y'/y²-1=0
y³cos(xy)+xy²y'cos(xy)+y'-y²=0
y'[xy²cos(xy)+1)=y²-y³cos(xy)
y'=[y²-y³cos(xy)]/[xy²cos(xy)+1]
当x=0,
sin(0*y)-1/y-0=1
-1/y=1
∴y=-1
∴y'|(x=0,y=-1)
=[(-1)²-(-1)³cos(0*(-1))/[0*(-1)²cos(0*(-1))+1]
=(1+1)*1/(0+1)=2/1
=2

直线X-√3y+√3=0 也即是y=√3x/3+1因为和椭圆C相交于顶点B和交点F而y=√3x/3+1的纵截距是1 横截距是-√3所以B(0,1) F(-√3,0)所以b=1 c=√3 那么a=√b^2+c^2=2所以x^2/4+y^2=1设P(x0,y0)设P到左准线的垂足为...