因式分解x3+x2+xy-xy2

逃掉的爱情2022-10-04 11:39:544条回答

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495446345 共回答了19个问题 | 采纳率94.7%: x^3+x^2+xy-xy^2
=x(x^2+x+y-y^2)
=x(x^2-y^2+x+y)
=x[(x+y)(x-y)+(x+y)]
=x(x+y)(x-y+1); 1年前

bolis82912 共回答了9个问题 | 采纳率: 原式 = (x3-xy2) + (x2+xy)
= x(x2-y2) + x(x+y)
= x(x+y)(x-y) + x(x+y)
= x(x+y)(x-y+1); 1年前

人生如梦999 共回答了16个问题 | 采纳率87.5%: 原式 = (x3-xy2) + (x2+xy)
= x(x2-y2) + x(x+y)
= x(x+y)(x-y) + x(x+y)
= x(x+y)(x-y+1); 1年前

爱你是错是对共回答了3个问题 | 采纳率: x(x+y)(x-y+1); 1年前

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