(x+10)分之一+(x+1)(x+2)分之一+(x+2)(x+3)分之一+~+(x+9)(x+10)分之一=2 解方程

轻风吹断2022-10-04 11:39:543条回答

已提交，审核后显示！提交回复

共3条回复

战台风0 共回答了28个问题 | 采纳率85.7%: 即1/(x+10)+1/(x+1)-1/(x+2)+1/(x+2)-1/(x+3)+……+1/(x+9)-1/(x+10)=2
所以1/(x+1)=2
x+1=1/2
x=-1/2; 1年前

lelefjl520 共回答了2089个问题 | 采纳率0.1%: 1/(x+10)+1/(x+1)(x+2)+1/(x+2)(x+3)+……+1/(x+9)(x+10)=2
1/(x+10)+1/(x+1)-1/(x+2)+1/(x+2)-1/(x+3)+……+1/(x+9)-1/(x+10)=2
1/(x+10)+1/(x+1)-1/(x+10)=2
1/(x+1)=2
x+1=1/2
x=1/2-1
x=-1/2（-2分之1）; 1年前

zy5122 共回答了511个问题 | 采纳率: 1/(x+10)+1/(x+1)(x+2)+1/(x+2)(x+3)+...+1/(x+9)(x+10)
=1/(x+10)+1/(x+1)-1/(x+2)+1/(x+2)-1/(x+3)+...+1/(x+9)-1/(x+10)
=1/(x+1)=2，
——》x=-1/2。; 1年前

相关推荐

x(x-1)分之一+x(x+1)分之一+········+(x+9)(x+10)分之一=12分之11 怎么算? 响当当的哈哈1年前1: gy0701 共回答了16个问题 | 采纳率93.8%

x(x-1)分之一+x(x+1)分之一+········+(x+9)(x+10)分之一
=1/(x-1)-1/x+1/x-1/(x+1)+.1/(x+9)-1/(x+10)
=1/(x-1)-1/(x+10)
=11/12
12(x+10-x+1)=11(x-1)(x+10)
12*11=11(x-1)(x+10)
12=(x-1)(x+10)
x^2+9x-22=0
(x+11)(x-2)=0
x=-11 或 x=2
经检验x=-11 或 x=2是方程的根

1年前查看全部

大家在问