（2/5mn^3-m^2n^2+1/6n^4)/(2/3n^2)=?

orbit_stu2022-10-04 11:39:542条回答

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zbgoodboy 共回答了21个问题 | 采纳率85.7%: （2/5mn^3-m^2n^2+1/6n^4)/(2/3n^2)
=2/5mn³÷2/3n²-m²n²÷2/3n²+1/6n^4÷2/3n²
=3/5mn-3/2m²-1/4n²; 1年前

yy冲刺中共回答了22个问题 | 采纳率: 原式=(2/5mn³÷2/3n²)-(m²n²÷2/3n²)+(1/6n^4÷2/3n²)
=(2/5÷2/3)×m×(n³÷n²)-(1÷2/3)×m²×(n²÷n²)+(1/6÷2/3)×(n^4÷n²)
=(3/5)×m×n^(3-2)-(3/2)×m²×1+(1/4)×n^(4-2)
=(3/5)mn-(3/2)m²+(1/4)n²; 1年前

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