流体力学英文题目(2),9.When the pipeinstallation changes from horizon

李社亮2022-10-04 11:39:541条回答

流体力学英文题目(2),
9.When the pipeinstallation changes from horizontal to vertical position and the velocitykeeps unchanged,the frictional loss will be .
A).increased; B).decreased; C).the same; D).uncertain
10.Fluid flows throughthe pipe at low flow rates,when the velocity rises in double time,thepressure drop in the fluid will( ).
11.For Newtonianfluids,if the typeof flow through the pipe is laminar flow,then its characteristics are:__________________________________;_______________________;________________________.
12.For given dust system the capacity of gravity settling chamber dependson ( )
A) The height and length ofchamber
B) height of chamber
C) The bottom area of chamber
D) Volume of chamber
13.For constant pressure filtration,if the filtering medium (septum)resistance is ignored,the filtering time is double and other operatingconditions keep unchanged,the filtrate volume will be ( )
(A)double; (B) half of original; (C) 21/2 of original; (D) uncertain
14.The critical diameter implies for the performance of cyclone旋风分离器 .
(A) minimum diameter of particleremoved completely by cyclone
(B) diameter of cyclone for maximum separationefficiency
(C) maximum diameter of particle tomaintain laminar flow
(D) minimum diameter of particleleaving the cyclone

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yama888 共回答了27个问题 | 采纳率88.9%
大致翻译一下,给你答案
9、当管道由水平变为垂直布置的时候,流速不变摩擦损失会怎样变化(B减少)
10、管道内流体在低速流动时(层流),当流速倍增时,压降损失会怎样(double,尼古拉斯公式)
11、对于牛顿流体,管道内流动为层流时,性质有:(符合牛顿内摩擦定律)(中间流速最大,向四周递减)(切应力与流速梯度的图象是过原点的直线)
12、对于给定的重力沉降室,其生产能力与什么有关(C与沉降室的底面积有关,与高度无关)
13、对于恒定压力过滤装置,如果其他条件不变,过滤时间变为两倍,则过滤体积为(C 根号2)
14、临界直径对于旋风分离器是什么意思(B 最大效率分离出来的最小粉尘粒子的直径(或当量直径))
1年前

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骑驴上天山1年前1
让我好好的睡 共回答了13个问题 | 采纳率84.6%
连通器原理
不管怎么样,两头都是一样位置的
压强只跟水深有关,跟形状没关系的
流体力学 作业 怎么翻译The flow of a lubricating oil of viscosity 0.2 P
流体力学 作业 怎么翻译
The flow of a lubricating oil of viscosity 0.2 Pa.s occurs in a friction bearing such as that shown in
Fig. A difference in velocity of 0.5 m/s between the upper plate (the rotating wheel) and the stationary
lower plate (the axle of diameter 5 cm) corresponds to a rate of rotation of 190.6 rpm in Fig. If the
length L of the bearing is 5 cm, calculate the rate at which mechanical energy is degraded to thermal
energy by friction during rotation at 190.6 rpm.
你这不是谷歌的吗 这也不通顺呀
红堂蓝烛1年前2
天二人 共回答了21个问题 | 采纳率90.5%
如图所示 ,在滑动轴承中,润滑油的 粘度0.2Pa.s,上、下板的速度差为 0.5 m/s(怀疑此处是指两板的间隙为0.5mm,这个题目要利用两板之间的间隙通过牛顿内摩擦定律求解,估计原英文为:A difference 0.5mm between the upper plate (the rotating wheel) and the stationary lower plate),上板即为转速为190.6 rpm的轴承套(内表面),下板即为静止不动、轴径为5cm轴颈(外表面).如果轴承长度为5cm,轴承套转速保持190.6 rpm时,试计算由于摩擦而引起的机械能转变为热能的速率.
(这个题其实就是要你把两表面之间的速度看成线性变化的,然后利用牛顿的内摩擦定律计算摩擦力,摩擦力在乘以角速度就是摩擦功率,由于摩擦而消耗的能量可以看成是发热而消耗了,所以这个摩擦功率就是发热功率,即发热的速率)