x-y/x²÷x²-2xy+y²/xy*(xy-x²)

cathygao20082022-10-04 11:39:542条回答

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支持顶帖23 共回答了15个问题 | 采纳率80%
(x-y)/x²÷(x²-2xy+y²)/xy×(xy-x²)=(x-y)/x²÷(x+y)²/xy×x(y-x)=(x-y)²/x²×xy/(x+y)²×x(y-x)=-(x-y)³/(x+y)²
1年前
mochunxia 共回答了307个问题 | 采纳率
x-y/x²÷x²-2xy+y²/xy*(xy-x²)
=x-y/x²×xy*(xy-x²)/(x-y)^2
=(x-y)/x^2×x^2y(y-x)/(x-y)^2
=-y
1年前

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原式=-x(x-y)*xy/(x-y)²*(x-y)/x²
=-x²y(x-y)²/[x²(x-y)²]
=-y