x^4-4x^3-3x^2+14x+12分解因式

dulang8862022-10-04 11:39:541条回答

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送213个香吻共回答了19个问题 | 采纳率94.7%: x^4-4x^3-3x^2+14x+12
=x^4-4x³+3x²-6x²+14x+12
=x²(x²-4x+3)-2(3x²-7x-6)
=x²(x-1)(x-3)-2(3x+2)(x-3)
=(x-3)(x³-x²-6x-4)
=(x-3)(x³-x²-2x-4x-4)
=(x-3)[x(x+1)(x-2)-4(x+1)]
=(x-3)(x+1)(x²-2x-4); 1年前

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