4m^4-4m^3+9m^2-12m+4=0怎么解

soloedge2022-10-04 11:39:541条回答

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abc808 共回答了21个问题 | 采纳率95.2%: 原式=(4m^4-4m^3+m^2)+(8m^2-4m)-8m+4
=m^2(2m-1)+4m(2m-1)-4(2m-1)
=(2m-1)(m^2+4m-4)
=0
所以2m-1=0或m^2+4m-4=0
m=1/2或m=-2+根号2或者m=-2-根号2; 1年前

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m^4-4m^3+4m^2-9因式分解 菠菜4561年前2: njh55 共回答了16个问题 | 采纳率93.8%

m^4-4m^3+4m^2-9
=m^2(m^2-4m+4)-9
=m^2(m-2)^2-9
=(m^2-2m)^2-3^2
=(m^2-2m+3)(m^2-2m-3)
=(m^2-2m+3)(m-3)(m+1)

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