海选用英语怎么说?

弯弯月儿挂林梢2022-10-04 11:39:542条回答

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vnymiko 共回答了22个问题 | 采纳率95.5%
海选:open audition
过关:make the cut)
被刷下去:get eliminated
1年前
鱼妹妹 共回答了15个问题 | 采纳率
first audition或者initial audition
1年前

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英文自我介绍范文2
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英文自我介绍范文3
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原则1.测试的重点考查的是你运用语言的能力,而不是对你的背景的了解.
2.自信
I am working for a XXXXX company as XXXXX(an assistant manager) in the XXXXX section.(我增经在XXXXX公司的XXXXX部门任XXXXX职位,比如经理助理).
In the company my job is to XXXX(develop new computer software) and I enjoy the job very much, because XXXX(software development is very creative and imaginative work). 在公司里我的工作是XXXX(开发新的电脑软件),我非常喜欢这个工作,因为XXXXX(软件开发是一项非常需要创造性和想象力的工作.:也就是凸现你有创造性和想象力)
The following XXXXX-year working experience offered me a good chance to give full play to my creativity, intelligence and diligence.(接下来的XXX年的工作经验让我得到了很大的发展)
What's more, I have taken a tour to some big company, through these i have a deeply understanding of XXXXX(computer software industry).(我还参观过一些大公司,通过这些,我对XXXXX(电脑软件工业)有了比较深刻的认识)
I choose to come here because I do think that company would XXXXXX(provide me a more challenge work and better develope chance)
(我选择到这里工作因为我认为公司XXXXX(说他的好处,能给我提供一份更具备挑战性的工作和更好的发展机会))
I do believe that with my solid educational background and ample working experience, I would be an excellent worker in your company.
(我相信以我过硬的教育背景以及工作经验,我会成为公司中出色的一员)
参考资料:http://zhidao.baidu.com/question/30688329.html?si=8
(2014•益阳模拟)甲、乙、丙三名音乐爱好者参加某电视台举办的演唱技能海选活动,在本次海选中有合格和不合格两个等级.若
(2014•益阳模拟)甲、乙、丙三名音乐爱好者参加某电视台举办的演唱技能海选活动,在本次海选中有合格和不合格两个等级.若海选合格记1分,海选不合格记0分.假设甲、乙、丙海选合格的概率分别为[2/3,
3
4
1
2],他们海选合格与不合格是相互独立的.
(Ⅰ)求在这次海选中,这三名音乐爱好者至少有一名海选合格的概率;
(Ⅱ)记在这次海选中,甲、乙、丙三名音乐爱好者所得分之和为随机变量ξ,求随机变量ξ的分布列和数学期望Eξ.
jim520 1年前 已收到1个回答 举报

calkchu 幼苗

共回答了24个问题采纳率:87.5% 举报

解题思路:(Ⅰ)记“甲海选合格”为事件A,“乙海选合格”为事件B,“丙海选合格”为事件C,“甲、乙、丙至少有一名海选合格”为事件E.利用对立事件的计算公式能求出结果.
(Ⅱ)ξ的所有可能取值为0,1,2,3.分别求出相对应的概率,由此能求出随机变量ξ的分布列和数学期望Eξ.

(本小题满分12分)
(Ⅰ)记“甲海选合格”为事件A,“乙海选合格”为事件B,
“丙海选合格”为事件C,“甲、乙、丙至少有一名海选合格”为事件E.
则P(E)=1−P(
.
A
.
B
.
C)=1−
1

1

1
2=
23
24.(4分)
(Ⅱ)ξ的所有可能取值为0,1,2,3.
P(ξ=0)=P(
.
A
.
B
.
C)=
1
24,
P(ξ=1)=P(A
.
B
.
C)+P(
.
AB
.
C)+P(
.
A
.
BC)=
6
24,
P(ξ=2)=P(AB
.
C)+P(A
.
BC)+P(
.
ABC)=
11
24,
P(ξ=3)=P(ABC)=
6
24.
∴ξ的分布列为

ξ 0 1 2 3
P [1/24] [6/24] [11/24] [6/24]Eξ=0×
1
24+1×
6
24+2×
11
24+3×
6
24=
23
12.(12分)

点评:
本题考点: 离散型随机变量的期望与方差;互斥事件的概率加法公式.

考点点评: 本题考查概率的求法,考查离散型随机变量的分布列和数学期望的求法,是中档题,在历年高考中都是必考题型之一.

1年前

4
可能相似的问题
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jim5201年前1
calkchu 共回答了24个问题 | 采纳率87.5%
解题思路:(Ⅰ)记“甲海选合格”为事件A,“乙海选合格”为事件B,“丙海选合格”为事件C,“甲、乙、丙至少有一名海选合格”为事件E.利用对立事件的计算公式能求出结果.
(Ⅱ)ξ的所有可能取值为0,1,2,3.分别求出相对应的概率,由此能求出随机变量ξ的分布列和数学期望Eξ.

(本小题满分12分)
(Ⅰ)记“甲海选合格”为事件A,“乙海选合格”为事件B,
“丙海选合格”为事件C,“甲、乙、丙至少有一名海选合格”为事件E.
则P(E)=1−P(
.
A
.
B
.
C)=1−
1

1

1
2=
23
24.(4分)
(Ⅱ)ξ的所有可能取值为0,1,2,3.
P(ξ=0)=P(
.
A
.
B
.
C)=
1
24,
P(ξ=1)=P(A
.
B
.
C)+P(
.
AB
.
C)+P(
.
A
.
BC)=
6
24,
P(ξ=2)=P(AB
.
C)+P(A
.
BC)+P(
.
ABC)=
11
24,
P(ξ=3)=P(ABC)=
6
24.
∴ξ的分布列为

ξ 0 1 2 3
P [1/24] [6/24] [11/24] [6/24]Eξ=0×
1
24+1×
6
24+2×
11
24+3×
6
24=
23
12.(12分)

点评:
本题考点: 离散型随机变量的期望与方差;互斥事件的概率加法公式.

考点点评: 本题考查概率的求法,考查离散型随机变量的分布列和数学期望的求法,是中档题,在历年高考中都是必考题型之一.

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关于即兴演讲刚刚海选演讲回来,应该进了,下一轮是初赛,里面有一个环节是即兴演讲,周五就比赛了,我没什么把握呢.希望能得到
关于即兴演讲
刚刚海选演讲回来,应该进了,下一轮是初赛,里面有一个环节是即兴演讲,周五就比赛了,我没什么把握呢.希望能得到你们的意见.
蛇蝎妹1年前1
拓展者 共回答了34个问题 | 采纳率88.2%
即兴演讲锻练的就是快速组织语言的能力,要想有好的发表一定要掌握说话的套路,只要你有套路就往里面加内容就行了,所以这个很简单,当掌握了方法那你平时就要练习了,例如走在路上你可以自己给自己出一些话题,坐车看到堵车了针对这些问题我觉得有以下几个原因造成的 1,2,3,4 针对这些问题我有4个建议1,2,3,4 就这样回答,所以要想即兴演讲能力不错就一定要掌握套路
更多即兴演讲套路baidu:张海翔无忧口才培训
超级女声的海选十分激烈 这句话有语病吗?超级女声还是超级女生?
whn13011年前1
盡情 共回答了14个问题 | 采纳率92.9%
这句话没有语病.超级女声.加引号