Solve for x in terms of n,A,B,C of log_b (A) + log_b (B) - l

可乐壁虎2022-10-04 11:39:541条回答

Solve for x in terms of n,A,B,C of log_b (A) + log_b (B) - log_b (C) = nlog_b (x)

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coco122 共回答了18个问题 | 采纳率94.4%
∵ log_b (A) + log_b (B) - log_b (C) = nlog_b (x)
∴ log_b [(AB)/C]=nlog_b (x)
∴ log_b (x)=(1/n)·log_b [(AB)/C]
∴ log_b (x)=log_b [(AB)/C]^(1/n)
∴ x= [(AB)/C]^(1/n)
1年前

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还用英文的,这年头~
1、解方程:(2p)2/3 + 12 = 76,即(2p)2/3 = 64,即(2p) = 32 * 3,p = 48.
2、解方程:13^-a = 1/169,即13^a = 169,a = 2.
3、还是解方程,写好一点才好看哦.大概是3^(1-2x) = 243,对吧?243 / 3 = 81 = 9^2 = 3^4,即3^(1-2x)= 3^5,即1-2x = 5,x = 2.
4、都是解方程,但这个不是方程,不懂!
5、又是解方程2^2t+1-4^t+2^2t-1 =24,即2^2t+1-2^2t+2^2t-1 =24,这到底是写的什么呢?我猜是
2^(2t+1)-2^2t+2^(2t-1) =24,令x = 2^2t,化成2x - x + x / 2 = 24,3x = 48,x = 16,则t = 4.
6、最后一个方程:(9^-1/2 g^3)除(2^-1 g^2) =2/3看不懂,括号里面都两个数之间都没连接符,我猜你还不会用到矩阵运算,打错了吧.
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