(a^m+b^n-2)(-2a^m-2b^n-2)^2(3a^m+3b^n-2)^3*(1/2b^n-2+1/2a^

笨笨8112022-10-04 11:39:541条回答

(a^m+b^n-2)*(-2a^m-2b^n-2)^2*(3a^m+3b^n-2)^3*(1/2b^n-2+1/2a^m)^4

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岩根共回答了15个问题 | 采纳率93.3%: (a^m+b^n-2)*(-2a^m-2b^n-2)^2*(3a^m+3b^n-2)^3*(1/2b^n-2+1/2a^m)^4
=(a^m+b^n-2)*(-2)^2*(a^m+b^n-2)^2*3^3(a^m+b^n-2)^3*(1/2)^4*(a^m+b^n-2)^4
=4*27/16*(a^m+b^n-2)^(1+2+3+4)
=27/4*(a^m+b^n-2)^10; 1年前

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