汽车动力性!已知某载货汽车满载重量38000N,车轮半径0.367m,传动系数机械效率0.85,滚动阻力系数0.013,

hj91572022-10-04 11:39:541条回答

汽车动力性!
已知某载货汽车满载重量38000N,车轮半径0.367m,传动系数机械效率0.85,滚动阻力系数0.013,空气阻力系数0.75,迎风面积3.8m²,传动系总传动比igio=18.0.现汽车以30km/h的速度匀速上坡,坡度i=0.01,试计算此时发动机曲轴输出转矩是多少?

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阿雅达 共回答了13个问题 | 采纳率76.9%
设坡角度为A tanA=0.01 算出A来.
匀速上坡 发动机牵引力=GcosAf+GsinA+风阻(自己查公式,电脑不好写)
算出发动机牵引力后除以车轮滚动半径得到车轮扭矩.
把车轮扭矩除以传动比再除以机械效率0.85即为发动机输出转矩.
1年前

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