sin^6a+cos^6a+3sin^2acos^2a的值为?

cc缘2022-10-04 11:39:542条回答

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yashee 共回答了16个问题 | 采纳率87.5%: sin^6a+cos^6a+3sin^2acos^2a
=（sin²a＋cos²a）（sin^4a-sin^2acos^2a+cos^4a）+3sin^2acos^2a
=sin^4a-sin^2acos^2a+cos^4a+3sin^2acos^2a
=sin^4a＋2sin^2acos^2a+cos^4a
=（sin²a＋cos²a）²
=1²
=1; 1年前

0509151 共回答了592个问题 | 采纳率: sin^6a+cos^6a+3sin^2acos^2a
=(sin^2a+cos^2a)(sin^4a-sin^2acos^2a+cos^4a)+3sin^2acos^2a
=sin^4a-sin^2acos^2a+cos^4a+3sin^2acos^2a
=sin^4a+2sin^2acos^2a+cos^4a
=(sin^2a+cos^2a)^2
=1^2
=1; 1年前

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